Help with a kinematics question

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Homework Help Overview

The problem involves kinematics, specifically the motion of water projected vertically from a nozzle. The scenario describes a garden hose nozzle adjusted to create a hard stream of water, with the water being released from a height of 1.5 meters and striking the ground after a delay of 2.0 seconds.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the kinematic equation for vertical motion, questioning the interpretation of variables such as initial position and time. There is an exploration of how to isolate the initial velocity from the equation.

Discussion Status

The discussion has progressed with participants clarifying the meaning of terms in the equation and working through the implications of their substitutions. Guidance has been provided regarding the interpretation of the initial position and the relationship between time and position.

Contextual Notes

There is an acknowledgment of the two variables present in the equation, leading to a discussion about how to resolve them. The participants are navigating through the assumptions related to the initial position and the time of flight.

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Homework Statement


Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5m above the ground. When you quickly move the nozzle away from the vertical, you hear the water striking the ground next to you for another 2.0 seconds. What is the water speed as it leaves the nozzle?

Homework Equations


I'm assuming you have to use the formula
x(t)=height + Vo * t - 1/2 * a * t^2

The Attempt at a Solution


So I plugged in the values given, and came up with this.

x(t)=1.5 + v(2) -1/2 * 10 * 2^2

x(t)=1.5 + v(2) - 20Now I'm kind of stuck though. It seems to me I have two variables, and nothing to do with them. Any help would be greatly appreciated.
 
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Hi danhamilton,

danhamilton said:

Homework Statement


Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5m above the ground. When you quickly move the nozzle away from the vertical, you hear the water striking the ground next to you for another 2.0 seconds. What is the water speed as it leaves the nozzle?


Homework Equations


I'm assuming you have to use the formula
x(t)=height + Vo * t - 1/2 * a * t^2

The Attempt at a Solution


So I plugged in the values given, and came up with this.

x(t)=1.5 + v(2) -1/2 * 10 * 2^2

x(t)=1.5 + v(2) - 20


Now I'm kind of stuck though. It seems to me I have two variables, and nothing to do with them. Any help would be greatly appreciated.

In your equation, you have labeled the first term on the right side as 'height'. That's true, but it's not just any height--it's the initial position (at t=0).

That's important because then on the left side x(t) is the position of the object at some time t. You've chosen t=2 (on the right side of the equation), so x(t) is the position at t=2. What would that be? Once you have that I believe you can solve for the initial speed.
 
I guess I meant initial position when I said height. So would that make x(t) 0?
 
Ok, so then
0 = 1.5 + v(2) - 20

18.5 = v(2)

So the initial velocity would be 9.25 m/s?
 
You got it.
 
Awesome, thank you guys so much for the help!
 

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