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nobelium102
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Homework Statement
Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5 m above the ground (the hose is 1.5 m off the ground). When you quickly move the nozzle from the vertical you hear the water striking the ground next to you for another 2.0 s. What is the water speed as it leaves the nozzle?
Homework Equations
?
The Attempt at a Solution
my attempt s = ut+1/2 at^2
-1.5 = u(2) + 1/2(-9.8)(4)
u = 9.05 m/s
and it is right
but the question is that why is the acceleration still -9.8m/s^2 when the water is going up and then falling down?