Help with algebra problem involving logs

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The discussion revolves around solving the equation (Log3 of x)(Logx of 2x)(Log2x of Y) = (log x of x^2) to find the value of Y. Participants emphasize the use of the change of base theorem, which states that log_g a = log a / log g, to simplify the logarithmic expressions. A suggestion is made to replace each logarithm with its corresponding change of base form to facilitate solving the equation. While Wolfram Alpha is referenced for potential solutions, it does not provide a direct answer, prompting users to analyze the generated graph instead. The conversation ultimately focuses on applying logarithmic properties to derive the value of Y.
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Do you know about the base changing theorem?
 
Welcome to PF, strike2kill! :smile:

strike2kill said:
If (Log3 of x )( Logx of 2x)(Log2x of Y) =(log x of x^2) what is the value of Y?

http://www.wolframalpha.com/input/?i=(Log3+of+x+)(+Logx+of+2x)(Log2x+of+Y)+=(log+x+of+x^2)

Wolfram Alpha gives me that but i need to know how to get there. THANKS!

What you would need is that ##\log_g a = {\log a \over \log g}##.
Can you find Y if you use this?


Btw, let's redo WolframAlpha with the proper expression:
http://www.wolframalpha.com/input/?i=log(3,+x)+*+log(x,++2x)+*+log(2x,+Y)+=+log(x,+x^2)
Actually Wolfram does not give the answer, although you can read it off the graph that it generates.
 
I'm sort of familiar with the change of base formula but I don't know how to apply it here
 
Replace (Log3 of x) by log(x)/log(3) and so on...
 
This has nothing to do with "Linear and Abstract Algebra" so I am moving it to "general mathematics".
 
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