Help with average value of a function

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Homework Help Overview

The discussion revolves around finding a number \( b \) such that the average value of the function \( f(x) = 1 + 10x - 3x^2 \) over the interval \([0, b]\) equals 4. Participants are exploring the concept of average value of a function in the context of calculus.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to set the average value equal to 4 but encounters difficulties in solving for \( b \). Some participants inquire about the method for calculating the average of a function over an interval and the relevant equation needed for this calculation.

Discussion Status

Participants are engaged in clarifying the process of finding the average value of a function and discussing the necessary steps to formulate an equation involving \( b \). There is an indication of guidance being offered regarding the integration of the function and the division by the interval length.

Contextual Notes

The original poster expresses frustration with their attempts to solve for \( b \), indicating a potential misunderstanding of the average value calculation process. There may be missing information or assumptions that are not fully articulated in the discussion.

credd741
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i have a question :cry:
how would you find a number b such that the average value of
f(x)= 1+10x-3x^2 on the interval [0,b] is equal to 4.

i have tried to set this equal to 4 but everytime i try to solve for b i get some number but it is always wrong. please help!:cry::cry::cry::cry:
 
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Welcome to the PF. How do you calculate the average of a function over an interval? What is the relevant equation?
 
the relevant equation is the f(x)=1+10x-3x^2
 
In order to find the average value of a function over a specified interval [0,b] you must integrate the function on that interval and divide by the interval length.

Can you formulate an equation which states these facts in terms of b and solve for b?
 

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