Help with BCD to Excces3 Code Converter using 3-8 Decoder & NAND

[AmOoly]

How to realize a BCD to Excces3 Code converter using only 3-8 Decoder(s) and four NAND gates?

 

[berkeman]

What does your first try look like? Oh, and this question should be posted in the Homework forums, BTW. Welcome to PF.

 

[piercas]

One possible solution for realizing a BCD to Excces3 Code converter using only a 3-8 Decoder and four NAND gates is as follows:

1. First, we need to understand the BCD and Excces3 code formats. BCD (Binary Coded Decimal) is a numeric code where each decimal digit is represented by a 4-bit binary number. Excces3 code is a type of binary code where the decimal value is represented by the excess of 3 of the binary number.

2. To convert BCD to Excces3 code, we need to add 3 to the BCD value and then convert it to binary. For example, if the BCD value is 0101, we add 3 to it, resulting in 0110. This is the Excces3 code for the decimal value 5.

3. Now, let's look at how we can use a 3-8 Decoder and NAND gates to implement this conversion. A 3-8 Decoder takes 3 inputs and produces 8 outputs based on the input combination. We can use the 3 BCD inputs (A, B, C) as the inputs for the Decoder and use the 8 outputs (Y0-Y7) as the inputs for the NAND gates.

4. The first step is to design the truth table for the 3-8 Decoder. The inputs A, B, C represent the BCD values, and the outputs Y0-Y7 represent the binary values of the Excces3 code.

5. Next, we need to use NAND gates to implement the logic of adding 3 to the BCD value. We can use four NAND gates in total, with two NAND gates for each BCD input (A, B, C).

6. The first NAND gate for each input will take the BCD input and its complement as the inputs. For example, for input A, the first NAND gate will take inputs A and A'. The output of this NAND gate will be connected to the corresponding input of the 3-8 Decoder.

7. The second NAND gate for each input will take the BCD input and the output of the first NAND gate as inputs. For example, for input A, the second NAND gate will take inputs A and (A AND A'). The output of this NAND gate will be connected to the corresponding input of the 3-8 Decoder.

8. The outputs of