Help with Integral: Find the area of C

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    Area Integral
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Homework Help Overview

The discussion revolves around evaluating an integral related to an elliptic spiral defined in parametric form. Participants are exploring the setup and transformation of the integral to facilitate solving for the area enclosed by the curve.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss rewriting the integral in different forms, including using dot products and parametric expressions. There are questions about the correctness of transformations and whether to separate integrals for clarity.

Discussion Status

The conversation includes attempts to clarify the integral's setup and transformations. Some participants provide guidance on rewriting the integral and checking the correctness of expressions, while others express uncertainty about the steps taken and seek confirmation.

Contextual Notes

There are indications of confusion regarding the application of parametric derivatives and the correctness of the integral transformations. Participants are also navigating the implications of the given parametric equations on the integral's evaluation.

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so have you tried anything?
 
here's how you can write it in tex
\int_C y dx-x dy +dz <br />

note you can re-write as a dot product, just for clarity
\int_C (y,-x,1) \bullet \vec{dx}

to solve, you just need to re-write the integral so you're only integrating over t
 
lanedance said:
here's how you can write it in tex
\int_C y dx-x dy +dz <br />

note you can re-write as a dot product, just for clarity
\int_C (y,-x,1) \bullet \vec{dx}

to solve, you just need to re-write the integral so you're only integrating over t

So the integral becomes \int_C [b*sint*dx-a*cost*dy+dz]
Which equals \int_C -a*b*cost*sint*dt-a*b*cost*cost*dt+c*dt ? And now should I separate the integrals?

Is that all I have to solve or is something wrong?
 
lanedance said:
here's how you can write it in tex
\int_C y dx-x dy +dz <br />

note you can re-write as a dot product, just for clarity
\int_C (y,-x,1) \bullet \vec{dx}

to solve, you just need to re-write the integral so you're only integrating over t

Or, a little neater write the integrand

\langle y, -x, 1\rangle \cdot \langle dx,dy,dz\rangle
 
gipc said:
So the integral becomes \int_C [b*sint*dx-a*cost*dy+dz]
Which equals \int_C -a*b*cost*sint*dt-a*b*cost*cost*dt+c*dt ? And now should I separate the integrals?

Is that all I have to solve or is something wrong?

so... is it okay to follow this steps?
 
gipc said:
So the integral becomes \int_C [b*sint*dx-a*cost*dy+dz]
Yes, that is correct.

Which equals \int_C -a*b*cost*sint*dt-a*b*cost*cost*dt+c*dt ?
No, that is not correct. You are given that x= a cos t so dx= -a sin(t). b sin t dx= (b sin t)(-a sin t dt)= -ab sin^2 t dt. y= b sin t so dy= b cos t dt. -a cos t dy= (-a cos t)(b cos t dt)= -ab cos^2 t dt. z= ct so dz= ct as you have.

And now should I separate the integrals?

Is that all I have to solve or is something wrong?
 

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