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**1. Homework Statement**

Internal moments need to equal external moments, work out the total of the internal moments. The object has a mass of 2 kg

**2. Homework Equations**

I have obtained

the moment about I (labelled as MI) + Iα

**3. The Attempt at a Solution**

the moment about I (MI)

Force in y direction = 2 kg x 12m/s^2 = 24 N.m

Force in x direction = 2 kg x 30m/s^2 = 60 N.m

(Force y x moment arm

*x*) = 24N.m x 5m = 120 N

(Force

*x*x moment arm

*y*) = 60 N.m x 10m = 600N

120N - 600N = -480 N

Iα = 3kg.m^2 x 10 rad/s^2 = 30 N

sorry I know I may have the units all jumbled

So the total internal moments = 600N + 30N = 630 N

the crunch for me is I dont actually get why the internal moment consists of Iα and the moment about point I.

What is Iα actually telling me ? I interpret it to mean that an object offers I resistance to being moved and it is moving at α, therefore it's force is Iα.

But if that is telling me the torque about that point why do we need to calculate the moment about the point as well to get the internal moment ?

thanks