MATLAB Help with MATLAB code; discrepancy between graph max and Matlab's max

AI Thread Summary
The MATLAB code is producing a discrepancy between the maximum value of Rf on the graph and the value returned by the max function. The maximum Vo difference is correctly identified as occurring at index 100,001, which corresponds to Rf being 10,000 ohms, not 100,001. The confusion arises because the max function returns an index rather than a direct value from the Rf array. Understanding that the maximum value of Vo_difference is tied to its index in the original Rf array clarifies the issue. This highlights the importance of interpreting MATLAB outputs correctly to avoid misinterpretations in data analysis.
babayevdavid
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Hi,

For some reason, when I run this MATLAB code, I'm getting what looks like about 10,000 for Rf for the largest Vo on the graph, but MATLAB is giving me Rf at (Vo)max as 100,001

Any ideas?

clc;
clear;
close all;

syms Rf

Rf = 0:0.1:100000;

VRt25 = 18.*(10000)./(10000 + Rf);
VRf25 = 18.*(Rf)./(10000 + Rf);

VRt2505 = 18.*(9977.81)./(9977.81 + Rf);
VRf2505 = 18.*(Rf)./(9977.81 + Rf);

V_difference25 = abs(VRt25 - VRf25);

V_difference2505 = abs(VRt2505 - VRf2505);

Vo_difference = abs(V_difference25 - V_difference2505);

figure;
plot(Rf,Vo_difference)
title('Voltage Difference Vo vs. Rf')
ylabel('Vo Difference [V]')
xlabel('Rf [ohms]')
hold on

%Maximum Vo Difference
[Vo_difference_max,Rf] = max(Vo_difference)
 
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There is no issue here.

Rf has 1,000,001 elements, as does Vo_difference.

The maximum of Vo_difference is 0.02, occurring at index 100,001. This means Vo_difference(100001) = 0.02.

The part you missed is that Rf(100001) = 10000 as expected. That is, the Rf you printed with max() gives you an index _into_ the original Rf, not a direct value of Rf.
 

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