Help with the Euler-Lagrange formula for a geodesic

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SUMMARY

The discussion centers on applying the Euler-Lagrange equation to derive the geodesic equation from the given metric \( ds^{2} = y^{2}(dx^{2} + dy^{2}) \). The user correctly identifies the expression for \( ds \) as \( ds = \sqrt{y + yy'^{2}} dx \) and formulates the functional \( F = \sqrt{y + yy'^{2}} \). The application of the Euler-Lagrange equation, specifically \( \frac{dF}{dy} - \frac{d}{dx}\left[\frac{dF}{dy'}\right] = 0 \), is noted, but the user expresses confusion regarding the presence of \( y^{2} \) inside the square root.

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martinhiggs
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Homework Statement



The metric is:

ds[tex]^{2}[/tex] = y[tex]^{2}[/tex](dx[tex]^{2}[/tex] + dy[tex]^{2}[/tex])

I have to find the equation relating x and y along a geodesic.

The Attempt at a Solution



ds = [tex]\sqrt{ydx^{2} + ydy^{2}}[/tex] - is this right?

ds = [tex]\sqrt{y + yy'^{2}}[/tex] dx

F = [tex]\sqrt{y + yy'^{2}}[/tex]

So then I apply the Euler-Lagrange equation

dF/dy - d/dx[dF/dy'] = 0Now I'm stuck, please help.
 
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It's a y^2 inside the square root, isn't it? Not a y.
 

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