Help with the physics of a Catapult

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    Catapult Physics
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The discussion focuses on optimizing a catapult design for a VEX robotics competition to achieve greater horizontal distance while minimizing vertical height. Key considerations include the launch angle, with a recommendation to aim for a 45-degree angle for maximum range, assuming equal launch and target heights. Participants emphasize the importance of ensuring the projectile does not slip during launch, as this can affect the angle and distance. The initial angle at which the projectile leaves the catapult arm is crucial, and adjustments may be needed to both the arm's stopping angle and the launch angle. Understanding projectile motion and applying the correct physics principles will enhance the catapult's performance.
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So currently i am working on a robot, and i have gone to my physics teacher on how to help me achieve what i want out of it but she was not detailed with her explanation. It is only her second year teaching physics so i don't blame her but this seemed like a good place to put it.

So this is for a competition called VEX robotics, i figured that could matter to any who wants to understand why i am asking but since it is a physics question i cam here. So currently my machine throws about 4 feet high but only 2 feet across. I just want to know is the physics behind designing a catapult so that i can figure out what can be accomplished to get more horizontal distance and a little less vertical distance. My Physics teacher said to look at the angle on the piece where the object sits, is this true and what should i look at? Please include any formulas because i do not understand where the angle comes into play. here is a picture when the machine is in the thrown position for reference, when it is down the outstretched c channel is parallel to the ground.
jhrl39.jpg
 
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Read up on projectile motion. The launch angle and velocity alter the range. Max range is typically achieved at a 45 degree launch angle if the launch point and target area are at the same height.
 
CWatters said:
Read up on projectile motion. The launch angle and velocity alter the range. Max range is typically achieved at a 45 degree launch angle if the launch point and target area are at the same height.
Ok thank you! But which angle should i be working to achieve 45? should it be the one that the object will be thrown on or the stop angle of the arm?
 
Change whatsoever you need so that the actual projectile launches at 45 degrees. You may need to change both of the angles you mention but I would start with the angle at which the arm stops.

Check that centrifugal force can't cause the projectile to slip out early as that will send it up at a steeper angle. Eg use a cup or similar on the arm to hold the projectile.
 
The equations: Projectile motion

The initial angle is the one when the projectile will leave the cup of your catapult, so usually when the arm will stop. As @CWatters said, this is assuming the projectile doesn't slide on the catapult as it moves up. In that case, you have to add the sliding velocity (as a vector) to the arm velocity to find the net velocity of the projectile and its true angle.
 
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