- #1

stonecoldgen

- 109

- 0

^{5}x)/([itex]\sqrt{sinx}[/itex])

I rewrote cos

^{5}x as cosx(1-sin

^{2}x)

^{2}, finally getting:

(cosx-2cosxsin

^{2}x+cosxsin

^{4}x)/[itex]\sqrt{sinx}[/itex]

and I don't even know if this is the correct path, so, any advice would be appreciated.