- #1
stonecoldgen
- 109
- 0
The problem is to find [itex]\int[/itex](cos5x)/([itex]\sqrt{sinx}[/itex])
I rewrote cos5x as cosx(1-sin2x)2, finally getting:
(cosx-2cosxsin2x+cosxsin4x)/[itex]\sqrt{sinx}[/itex]
and I don't even know if this is the correct path, so, any advice would be appreciated.
I rewrote cos5x as cosx(1-sin2x)2, finally getting:
(cosx-2cosxsin2x+cosxsin4x)/[itex]\sqrt{sinx}[/itex]
and I don't even know if this is the correct path, so, any advice would be appreciated.