Help with trigonometric integration problem

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SUMMARY

The discussion centers on solving the integral \(\int \frac{\cos(5x)}{\sqrt{\sin(x)}} \, dx\). The user rewrote \(\cos(5x)\) as \(\cos(x)(1 - \sin^2(2x))^2\) and expressed the integral as \(\frac{\cos(x) - 2\cos(x)\sin^2(2x) + \cos(x)\sin(4x)}{\sqrt{\sin(x)}}\). The conversation emphasizes the substitution \(t = \sin(x)\) to simplify the integral further. Ultimately, the user successfully found the solution.

PREREQUISITES
  • Understanding of trigonometric identities, specifically for cosine functions.
  • Familiarity with integration techniques, particularly trigonometric integration.
  • Knowledge of substitution methods in calculus.
  • Ability to manipulate square roots in integrals.
NEXT STEPS
  • Study trigonometric identities and their applications in integration.
  • Learn advanced integration techniques, focusing on trigonometric integrals.
  • Explore substitution methods in calculus, particularly for integrals involving square roots.
  • Practice solving integrals with varying trigonometric functions and substitutions.
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Students and educators in calculus, mathematicians focusing on integration techniques, and anyone looking to enhance their skills in solving trigonometric integrals.

stonecoldgen
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The problem is to find [itex]\int[/itex](cos5x)/([itex]\sqrt{sinx}[/itex])

I rewrote cos5x as cosx(1-sin2x)2, finally getting:

(cosx-2cosxsin2x+cosxsin4x)/[itex]\sqrt{sinx}[/itex]

and I don't even know if this is the correct path, so, any advice would be appreciated.
 
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Re-write your integral replacing cos5x with what you have in your second line.

Now if you put t=sinx, what is dt?
 
rock.freak667 said:
Re-write your integral replacing cos5x with what you have in your second line.

Now if you put t=sinx, what is dt?

Thanks! I have the answer!
 

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