HELPPP, Integral of Tan^3(PI times X)dx

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SUMMARY

The integral of Tan^3(πX)dx can be approached using integration techniques involving trigonometric identities and substitution. The discussion highlights the transformation of the integral into two parts: ∫tan(πx) sec²(πx) dx and -∫tan(πx) dx. A substitution of u = tan(πx) is recommended for the first integral, while the second integral can be simplified by rewriting tan as sin/cos. This method leads to a clearer path for solving the integral.

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Homework Statement


Integral of Tan^3(PiX)dx


Homework Equations





The Attempt at a Solution


Int= Integral
PI=22/7
Int Tan^3(22/7X)dx
=Int Tan(22/7X)Tan^2(22/7X)dx
=Int (Sec^2(22/7X)-1)(Tan(22/7X)dx
=Int (Tan(22/7X)Sec^2(22/7X)-Tan(22/7X)dx
=...?
Im lost as to where to go from here, should i use a U substitution for one of them?
 
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Split the integral as two integrals now.

so you have

∫tan(πx) sec2(πx) dx - ∫ tan(πx) dx

for the first integral, you can use u=tan(πx) and for the second one, rewrite tan as sin/cos.
 
oooh, i don't know how i didnt seen that before, thanks a lot man
 
I = \int \tan^3 x \, dx = - \int d\cos x \, \frac{1-\cos^2 x}{\cos^3 x} = ...
 

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