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HighSchool Calculus Polynomial Division Help

  1. Feb 14, 2006 #1
    I was just doing my homework when I stumbled on this question. I don't understand it and I was wondering if someone could help me through it (don't just do it though, because I wanna learn HOW to do it :smile: )

    When 8x^3+4x^2-px+6, p E R, is divided by 2x-1, the remainer is 3. Determine the value of p.

    Thank you (And sorry about the question, I don't know how to use the LaTex stuff yet)
     
  2. jcsd
  3. Feb 14, 2006 #2

    TD

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    Have you ever done a 'long division' on polynomials, perhaps easier ones?
     
  4. Feb 14, 2006 #3
    Yeah, then I hit this question and I got lost. The unit is Chapter 1.4-Dividing Polynomials
     
  5. Feb 14, 2006 #4
    I'm confused, I didn't use any calculus at all to solve it. This is how I did it...I used polynomial division (I'm assuming you can do that reasonably well), and then towards the end, I got (-p+4)x = -6x, and then solved that. This would be so much easier if I had a web cam to show my working. It would also make much more sense to you, since I wouldn't be surprised if you had no idea what I was talking about.
     
  6. Feb 14, 2006 #5
    Just do polynomial division as usual until you get the remainer (which should contain the variable p). Equal that to 3 and you'll get the answer.
     
  7. Feb 14, 2006 #6

    TD

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    Although it's a bit more work, the method is the same for larger polynomials and you can just consider p as an unknown parameter for now. See if you can get started on the division, unfortunately it's rather hard to display such a long division on the forum.
     
  8. Feb 14, 2006 #7
    I wrote it out but I think I'm doing something wrong. While dividing, I get to the step 8x^2-px - 8x^2-4x
     
  9. Feb 14, 2006 #8

    TD

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    Assuming that you mean [itex]8x^2-px - (8x^2-4x)[/itex], that's fine since that equals [itex]x(p-4)[/itex] which is exactly what finchie_88 found as well so I think you're on track!
     
  10. Feb 14, 2006 #9
    OHH I SEE NOW. I get -px+4x, so I factor the x out?
     
  11. Feb 14, 2006 #10
    I got it! THank you so much XD
     
  12. Feb 14, 2006 #11

    TD

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    Great :smile:
     
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