How far does an 800 g hollow sphere roll up a 25-degree incline?

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SUMMARY

The discussion centers on calculating the distance an 800 g hollow sphere rolls up a 25-degree incline before stopping and reversing direction. The sphere has a diameter of 40.0 cm and an initial velocity of 4 m/s. Key equations used include the rolling kinetic energy formula, Krolling = 1/2Iw^2 + 1/2Mv^2, and the moment of inertia for a hollow sphere, I = 2/3MR^2. The problem is identified as an energy conservation question, where kinetic energy is converted into gravitational potential energy.

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  • Understanding of kinetic energy and potential energy concepts
  • Familiarity with the moment of inertia for hollow objects
  • Knowledge of basic trigonometry for incline calculations
  • Ability to apply energy conservation principles in physics
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  • Study the conservation of energy in rolling motion
  • Learn about the dynamics of rolling objects on inclines
  • Explore the derivation of the moment of inertia for various shapes
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Homework Statement



An 800 g, 40.0 cm diameter hollow sphere is rolling along at 4 m/s when it comes to a 25 degree incline. Ignoring any friction, how far along the incline does it roll before it stops and reverses its direction?



Homework Equations



Krolling= 1/2Iw^2 + 1/2Mv^2
I=2/3MR^2

The Attempt at a Solution


Too difficult to type
 
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It looks like an energy question to me!
 

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