Holstein Primakoff representation

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SUMMARY

The Holstein Primakoff representation is defined by the equations: \(\hat{S}^+_m=\sqrt{2S}\sqrt{1-\frac{\hat{B}_m^+\hat{B}_m}{2S}}\hat{B}_m\), \(\hat{S}_m^-=(\hat{S}^+_m)^+\), and \(\hat{S}_m^z=S-\hat{B}_m^+\hat{B}_m\). The use of the binomial series for the square root is valid under the condition \(\frac{ \langle \hat{B}_m^+\hat{B}_m \rangle}{2S}<<1\), which typically requires \(S>>\frac{1}{2}\). However, the representation is frequently applied in cases where \(S=\frac{1}{2}\), as the Taylor series for the root converges adequately for this value, particularly when \(\hat{B}_m^+\hat{B}_m\) equals 1 or 0.

PREREQUISITES
  • Understanding of quantum mechanics and spin operators
  • Familiarity with the Holstein Primakoff transformation
  • Knowledge of Taylor and binomial series expansions
  • Basic concepts of quantum field theory
NEXT STEPS
  • Study the implications of the Holstein Primakoff representation in quantum mechanics
  • Explore the conditions for the convergence of Taylor series in quantum applications
  • Investigate the role of spin operators in quantum field theory
  • Examine practical examples of Holstein Primakoff representation in recent research papers
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Physicists, particularly those specializing in quantum mechanics and quantum field theory, as well as researchers exploring spin systems and their representations.

LagrangeEuler
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Holstein Primakoff representation in textbooks is defined by:
\hat{S}^+_m=\sqrt{2S}\sqrt{1-\frac{\hat{B}_m^+\hat{B}_m}{2S}}\hat{B}_m
\hat{S}_m^-=(\hat{S}^+_m)^+
\hat{S}_m^z=S-\hat{B}_m^+\hat{B}_m
And in practical cases it is often to use binomial series for square root, and condition for that is
##\frac{ \langle \hat{B}_m^+\hat{B}_m \rangle}{2S}<<1 ## and because of that I can use binomial series only in case ##S>>\frac{1}{2}##. However, it is very often to use that in case ##S=\frac{1}{2}## in papers. Any explanation?
 
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The Taylor series for the root still converges well for S=1/2 and ##b^+b=1## or 0 (other values don't occur). Test it yourself.
 

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