Homework: Solving for Energy Conducted dQ/dt

  • Thread starter Thread starter encorelui2
  • Start date Start date
  • Tags Tags
    Energy Homework
Click For Summary

Homework Help Overview

The discussion revolves around a problem related to heat conduction, specifically focusing on deriving the rate of energy conducted, denoted as dQ/dt, in a cylindrical geometry where the temperatures Ta and Tb differ. The original poster expresses confusion regarding the derivation of an equation for the medium area involved in the heat transfer process.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between temperature differences and heat conduction, mentioning proportionality to temperature change. Some participants inquire about relevant formulas and concepts related to heat conduction, while others ask for clarification on specific notes and equations that may apply to the problem.

Discussion Status

Participants are actively engaging in clarifying the requirements for a valid solution attempt. Some guidance has been offered regarding the need for clearer presentation of the original poster's work, emphasizing the importance of legibility and structured responses. Multiple interpretations of the problem are being explored, particularly concerning the application of heat conduction principles.

Contextual Notes

The original poster has not provided a clear solution attempt, which is a requirement for further assistance. There are indications of constraints related to the clarity of submitted materials and the necessity for a more structured approach to presenting their understanding of the problem.

encorelui2
Messages
7
Reaction score
0

Homework Statement



See attached figure. Ta>Tb. Show that the rate of energy conducted dQ/dt is 2*pi*L*k((Ta-Tb)/Ln(b/a))

Homework Equations

The Attempt at a Solution


I seem to be lost at deriving an equation for the medium area, A.
I understand the tansfer from low temp area to high. Pcond. is proportional to change in temp from H to L temp areas. I have attached my attempt at a soln.
 

Attachments

  • 20170212_182525-1.jpg
    20170212_182525-1.jpg
    28.1 KB · Views: 458
  • 20170212_190904.jpg
    20170212_190904.jpg
    33.8 KB · Views: 436
Last edited:
Physics news on Phys.org
This forum requires you to show some work towards a solution before we can help you.

What have you learned about heat conduction that you think might be relevant? Do you know how to calculate the rate of heat flow through a thin slab of material? Do you know any formulas that might be helpful?
 
Which parts of your notes shown below apply specifically to this problem?
upload_2017-2-12_21-32-35.png
 
If the radial temperature gradient is dT/dr, what is the rate of heat flow through the cylindrical surface at radius r (inside the conductor)?
 
@encorelui2 : An image of class notes does not comprise a solution attempt, particularly an image that is essentially illegible due to poor image quality and small handwriting (your personal handwriting may be clear as day to you, but it's close to a secret code to others when it's tiny and fuzzy and low contrast). Please provide an acceptable solution attempt or at least describe what approaches you've tried. If you use an image, be sure number every equation on the page so that helpers can refer to them in their responses.

If your images are not clear enough to read then you need to type in your attempt. Text-formatted math can be rendered using the icon tools in the edit panel header or using LaTeX syntax. It's much easier for helpers to read, quote, and comment on typed-in content and experience shows that you'll more, and more timely help responses that way.

Note that without a valid solution attempt your thread is in danger of being removed. See:
Hey! I posted here but now it's gone!
 
  • Like
Likes   Reactions: Chestermiller

Similar threads

  • · Replies 15 ·
Replies
15
Views
25K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
2
Views
9K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K