Homogeneization of physic formula of electromagnetic field and velocity

Click For Summary
SUMMARY

The discussion centers on the confusion surrounding the units of electric potential (\vec A) and velocity (\vec v) in electromagnetic field equations. The participant mistakenly equates the units of electric potential with velocity, leading to the incorrect interpretation of volts per velocity. The correct unit for \vec A is Tesla·m, not m/s, which clarifies the discrepancies in the calculations involving the magnetic field and velocity. The participant is advised to correctly utilize power equations to resolve the inconsistencies in their formulas.

PREREQUISITES
  • Understanding of electromagnetic field theory
  • Familiarity with units of measurement in physics
  • Knowledge of vector calculus and the del operator
  • Basic principles of power equations in electrical systems
NEXT STEPS
  • Study the relationship between electric potential and magnetic fields in electromagnetic theory
  • Learn about the correct units and dimensions of Tesla and electric potential
  • Research vector calculus applications in physics, specifically the del operator
  • Explore power equations and their implications in electrical engineering
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone involved in the study of electromagnetic fields and their mathematical representations.

Plott029
Messages
12
Reaction score
0
https://www.youtube.com/watch?v= I have a little problem with a formula, that I think it's not ok. It gives to me the result of units of electric potential ([tex]\vec A[/tex]) and velocity [tex]\vec v[/tex]. The result seems to be volts per velocity, and I don't know it there exists this unit, or is a mistake.

In other hand, when i try to develope the units of the magnetic field, if i use [tex]\vec v X \nabla X \vec A[/tex] it gives to me units of diference of potential per unit of time:

[tex]\frac {[L]}{[T} \frac {1}{[L]} \frac {[L]}{[T]} = <u>/[T]</u>[/tex]

and using tesla x velocity, it gives different result:
[tex]\frac {[L][M]}{[T]^3 <i>} </i>[/tex]

I don't know what I'm not doing correctly. Could you give me a little help?

Thanks.
 
Physics news on Phys.org
Maybe the problem is that I must utilize power ecuations... like UI and FV. The problem now is that I have an equation that has UIFV, with dimensions of power^2...
 
Plott029 said:
https://www.youtube.com/watch?v= I have a little problem with a formula, that I think it's not ok. It gives to me the result of units of electric potential ([tex]\vec A[/tex]) and velocity [tex]\vec v[/tex]. The result seems to be volts per velocity, and I don't know it there exists this unit, or is a mistake.

In other hand, when i try to develope the units of the magnetic field, if i use [tex]\vec v X \nabla X \vec A[/tex] it gives to me units of diference of potential per unit of time:

[tex]\frac {[L]}{[T} \frac {1}{[L]} \frac {[L]}{[T]} = <u>/[T]</u>[/tex]

I don't understand what you did here. Okay, I see that
v → L/T
del operator → 1/L
but why do you say
A → L/T ?​
A has units of Tesla·m, not m/s as you are implying.

and using tesla x velocity, it gives different result:
[tex]\frac {[L][M]}{[T]^3 <i>} </i>[/tex]

This is correct.

I don't know what I'm not doing correctly. Could you give me a little help?

Thanks.
See above; it looks like you incorrectly equated A with a velocity.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
914
  • · Replies 3 ·
Replies
3
Views
2K
Replies
18
Views
2K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
1
Views
2K