Hooke's Law: Two springs in series

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SUMMARY

The equation for two springs in series is derived as K = [(1/k1) + (1/k2)]^-1, where K represents the equivalent spring constant. The force exerted by each spring is equal, expressed as F = k1x1 = k2x2, confirming that the tension in both springs is the same. This relationship is crucial for understanding how multiple springs interact under load. The discussion highlights the importance of grasping the fundamental principles of Hooke's Law to apply this knowledge effectively.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of algebra and equations
  • Familiarity with force and displacement concepts
  • Ability to interpret physics derivations and proofs
NEXT STEPS
  • Study the derivation of Hooke's Law for multiple springs
  • Learn about the implications of spring constants in mechanical systems
  • Explore applications of Hooke's Law in real-world engineering problems
  • Investigate the behavior of springs in parallel versus series configurations
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Students of physics, mechanical engineers, and anyone interested in understanding the mechanics of springs and their applications in various systems.

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[SOLVED] Hooke's Law: Two springs in series

can someone explain and prove to me why the equation for two springs in series is
K= [(1/k1)+(1/k2)]^-1 ?

this is how far i got
F= -k ∆x
F= -k (x1+x2)
 
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thanks
i looked at it but i don't understand this part

"Meanwhile, the force on the point between the two springs is
Fs = -k1x1+k2(x2-x1)"
 
The proof on that website is rather obscure. Instead, try this: What's the force exerted by each spring and by both springs?

F = k1x1 = k2x2 = k(x1 + x2)

Play around with this and you should be able to figure out k in terms of k1 and k2.
 
thanks doc al
this might be a stupid question
but k1x1 = k2x2 is it because the tension of both spring are equal?
 
Because the force is the same,yes
 
kk i think i got it
thanks for helping me =]
 

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