Horizontal and Vertical Velocity of a Truck on a 10 Degree Incline

[Miraploy]

A truck travels up a hill at a 10 degrees incline with constant speed of 30 m/s

What is horizontal component of the truck's velocity? What is vertical component of the truck's velocity?

 

[Tom McCurdy]

30 sin 10 equals vertical
30 cos 10 equals horizontal

 

[wais]

The horizontal component of the truck's velocity would be 30 m/s, as it is moving at a constant speed along the incline. The vertical component of the truck's velocity can be calculated using trigonometric functions, specifically the sine and cosine of the incline angle. Since the incline is at a 10 degree angle, the vertical component would be 30 m/s multiplied by the sine of 10 degrees, which is approximately 5.21 m/s. This means that the truck is also moving upward at a rate of 5.21 m/s while traveling at a constant speed of 30 m/s along the incline.