Horizontal Force in Pipe Bending

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SUMMARY

The discussion focuses on calculating the horizontal force required to hold a pipe in place as water flows through a bend, specifically from a diameter of 40mm to 25mm. Key parameters include a flow rate (Q) of 0.01 m³/s, initial and final areas (A1 and A2), velocities (u1 and u2), pressures (p1 and p2), and an angle (θ) of 60°. The calculated horizontal force (Fx) using the equation Fx = p2A2cosθ - p1A1 - m(u2cosθ - u1) yields a result of -0.011241193 N, indicating a need to interpret the sign of the force correctly. A sketch of the scenario is recommended for clarity in force direction.

PREREQUISITES
  • Fluid dynamics principles, particularly Bernoulli's equation
  • Understanding of pipe flow and area contraction effects
  • Basic mechanics of forces and equilibrium
  • Ability to perform dimensional analysis and unit conversions
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  • Study Bernoulli's equation and its applications in pipe flow
  • Learn about force balance in fluid systems
  • Research the effects of area contraction on flow velocity and pressure
  • Explore graphical methods for visualizing forces in fluid mechanics
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Engineering students, fluid mechanics practitioners, and anyone involved in the design and analysis of piping systems will benefit from this discussion.

adam640
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Homework Statement


Water enters a pipe and goes through a bend with a contraction from 40mm to 25mm then into the atmosphere.
What is the horizontal force required to hold the pipe in place?

Homework Equations


I have either been given the following or have calculated them using the standard formula, I am confident that they are correct.

Q = 0.01m3s-1
A1 = 1.26 x 10-3m2
A2 = 4.91 x 10-4m2
u1 = 7.94ms-1
u2 = 20.37ms-1
p1 = 31.52Pa
p2 = 207.47Pa
θ = 60°
ρ = 1kgm-3
m = u1A1ρ = 0.0100044

The Attempt at a Solution


Fx = p2A2cosθ-p1A1-m(u2cosθ-u1)

Using the above equation that I found from a few online sources I get the result:
-0.011241193N

So does this mean I multiply my answer my -1 to make it positive and this is the final result? Or have I gone wrong in my equation?

Any help is appreciated,

Adam
 
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You should always draw an sketch of the situation and place a force, Fx, on it. Then do a force balance to determine Fx. If Fx < 0, it will actually point in the opposite direction from the way you drew it.

In your case if you drew the sketch, Fx would be pointing in the direction of the force denoted by P1A1.
 

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