1. The problem statement, all variables and given/known data A block of 5 kg is on plane that is inclined of 37°, an outward (It is not directed toward the plane but it drags the the block horizontally away) horizontal force of 50 N is applied on the . The friction coefficient of that plane is 0,30. What is the total force that is applied in the perpendicular direction to the plane? (The book gives 9,0 N answer) 2. Relevant equations F=m*a 3. The attempt at a solution So...there is something i can't understand. I know that on anything that is on a plane, there is a normal force N that is the reaction. But i don't in this case...Shouldn't be the total force in the (y) direction 0? Shouldn't N be Py (Weight force in y direction) - Fy (Component in y direction of the horizontal force)? If the total force in y direction isn't 0, then doesn't the body goes away from the plane itself?