How Accurate is the Formula for Arrow Velocity from a Bow?

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SUMMARY

The discussion centers on the formula for calculating the velocity of an arrow released from a bow, specifically a leaf spring bow. The formula presented is V = √(2F_{av}S_f10 / (m_d + (1/2)m_fR^{-1})), where S_f is the spring tip movement, m_f is the spring weight, and m_d is the arrow weight. The user concludes that the velocity is directly proportional to the ratios of the arrow's mass to the spring's mass and the distances involved. The conversation highlights the importance of considering both the arrow and spring mass in the calculations, while also suggesting that air resistance and friction can be neglected for initial velocity assessments.

PREREQUISITES
  • Understanding of basic physics concepts, particularly mechanics.
  • Familiarity with the formula for kinetic energy and its relation to velocity.
  • Knowledge of spring mechanics and Hooke's Law.
  • Ability to manipulate algebraic equations and perform unit conversions.
NEXT STEPS
  • Research the derivation of the kinetic energy formula in relation to spring mechanics.
  • Explore the effects of air resistance on projectile motion using computational simulations.
  • Learn about advanced topics in dynamics, such as energy conservation in mechanical systems.
  • Investigate the impact of different spring materials on arrow velocity and performance.
USEFUL FOR

This discussion is beneficial for physics students, archery enthusiasts, and engineers interested in the mechanics of projectile motion and spring dynamics.

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Speed of an arrow from a bow (Latex format)

I am trying to determine the function for the velocity of an arrow out of a bow (leaf spring).
I am talking without considering factors such as air resistance and friction. I came up with:

<br /> V=\sqrt{ \frac {2F_{av}S_f10}{m_d+ \frac {1}{2}m_fR^{-1}}} <br />

S_f= Spring tip movement in meters;
S_d= Arrow's run in meters;
m_f= Spring weight in Kg;
m_d= Arrow weight in Kg;
F_{av}= Average force exerted by the spring along S_f in Newtons;
<br /> R=\frac {S_d}{S_f}<br />

Using this formula I got results which appear right:

Overall V appears to be directly proportional to arrow to spring ratios in mass and distance.

Still I am unsure about it. Is it right?
If so, is there a more elegant formulation?
 
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im not exactly an expert, but it seems to me like air ressistance and friction won't be flawing any simpler calcuations too greatly when your talking about the initial velocity, i wouldent even bother with them, mabye again that's because i can't exactly follow your equation, explain how you came up with it, i know i recoginse the format... honestly don't remember from what equation, but tell me how you ahve derived it and ill check over the math once I am sure there is no inherent flaw if you don't mind.
 
It would help if you provided a derivation of this proof. Can't help you otherwise.
 
This problem is being discussed in the Introductory Physics homework section.

https://www.physicsforums.com/showthread.php?t=123957

Not only does one have to consider the mass of the arrow, but also the mass of the spring, which is distributed along the spring.
 

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