Need a bit of help with arrow speed.

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  • Thread starter Thread starter wateroksnmud
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SUMMARY

The discussion centers on creating a calculator to determine the speed of an arrow based on the weight behind the string (X) and the weight of the arrow in grains (Y). The user, a freshman archer, seeks guidance on the relevant physics formulas and calculations necessary for this project. Key resources mentioned include nolimitsarchery.com and several physics-related websites that provide insights into archery mechanics. The user expresses a strong interest in math and aims to develop this tool for a personal website.

PREREQUISITES
  • Understanding of basic physics principles related to projectile motion
  • Familiarity with the formula for calculating velocity
  • Knowledge of archery equipment specifications, particularly arrow weight
  • Basic programming skills for implementing the calculator on a website
NEXT STEPS
  • Research the physics of projectile motion and the relevant equations
  • Learn how to calculate velocity using the formula: velocity = distance/time
  • Explore online resources for archery physics, such as mrfizzix.com
  • Investigate programming languages suitable for web development, such as JavaScript, to build the calculator
USEFUL FOR

This discussion is beneficial for archers, physics students, web developers, and anyone interested in the mechanics of archery and projectile motion calculations.

wateroksnmud
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Hi! To start off I am an archer. I'm currently a freshmen working towards my degree but have not yet made it to physics. The issue is that I need to create a calculator that I can use to find the speed of an arrow being shot from a bow when I have X (the weight behind the string) and Y (the weight of the arrow in grains). Where do I even start?

I have read some of the posts in here as I love math and would love to do this myself, but a lot of the formula's look like hieroglyphics right now.

This is calculator is not homework but for a site I'm building. You can see it nolimitsarchery.com

I appreciate any help in advance.
 
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