How Accurate is the Formula for Arrow Velocity from a Bow?

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Discussion Overview

The discussion centers on the formula for calculating the velocity of an arrow released from a bow, specifically a leaf spring bow. Participants explore the implications of various factors affecting the velocity, while also considering the derivation of the proposed formula.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant presents a formula for arrow velocity, noting it does not account for air resistance or friction, and expresses uncertainty about its correctness.
  • Another participant suggests that air resistance and friction may not significantly impact initial velocity calculations and requests clarification on the derivation of the formula.
  • A different participant emphasizes the need for a derivation of the formula to provide meaningful assistance.
  • One participant points out that the mass of both the arrow and the spring should be considered, mentioning that the mass of the spring is distributed along its length.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the validity of the formula or its derivation, and multiple viewpoints regarding the factors influencing arrow velocity remain present.

Contextual Notes

There are limitations regarding the assumptions made in the formula, particularly the neglect of air resistance and friction, as well as the treatment of the spring's mass distribution.

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Speed of an arrow from a bow (Latex format)

I am trying to determine the function for the velocity of an arrow out of a bow (leaf spring).
I am talking without considering factors such as air resistance and friction. I came up with:

<br /> V=\sqrt{ \frac {2F_{av}S_f10}{m_d+ \frac {1}{2}m_fR^{-1}}} <br />

S_f= Spring tip movement in meters;
S_d= Arrow's run in meters;
m_f= Spring weight in Kg;
m_d= Arrow weight in Kg;
F_{av}= Average force exerted by the spring along S_f in Newtons;
<br /> R=\frac {S_d}{S_f}<br />

Using this formula I got results which appear right:

Overall V appears to be directly proportional to arrow to spring ratios in mass and distance.

Still I am unsure about it. Is it right?
If so, is there a more elegant formulation?
 
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im not exactly an expert, but it seems to me like air ressistance and friction won't be flawing any simpler calcuations too greatly when your talking about the initial velocity, i wouldent even bother with them, mabye again that's because i can't exactly follow your equation, explain how you came up with it, i know i recoginse the format... honestly don't remember from what equation, but tell me how you ahve derived it and ill check over the math once I am sure there is no inherent flaw if you don't mind.
 
It would help if you provided a derivation of this proof. Can't help you otherwise.
 
This problem is being discussed in the Introductory Physics homework section.

https://www.physicsforums.com/showthread.php?t=123957

Not only does one have to consider the mass of the arrow, but also the mass of the spring, which is distributed along the spring.
 

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