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How can EM waves maintain their energy over infinite distance?

  1. Oct 26, 2014 #1
    EM field strength dies quickly with distance, what's so special about going up and down that allows EM waves to maintain their energy over infinite distance?
     
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  3. Oct 27, 2014 #2

    Simon Bridge

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    EM waves retain their total energy in accordance with the law of conservation of energy.
     
  4. Oct 27, 2014 #3
    What? Strength of electric field dies out quickly with distance. Why does the strength of an electric field going up and down not die out quickly with distance?
     
  5. Oct 27, 2014 #4

    Simon Bridge

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    The electric field in the EM waves propagates because it is being generated by a changing magnetic field. In the static case, there is no changing magnetic field to generate more electric field. But it is difficult to see what you are asking - in general, the amplitude of an EM wave will decrease with distance from the source.
     
  6. Oct 27, 2014 #5
    How does a changing magnetic field generate a changing electric field and vice versa?
     
  7. Oct 27, 2014 #6

    Nugatory

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    The relationship between the electrical and magnetic fields at any given point in space is given by Maxwell's equations. Google for "Maxwell equations", but be prepared to deal with a fair amount of vector calculus.
     
  8. Oct 27, 2014 #7
    But I am looking for a physical explanation, not a mathematical one.
     
  9. Oct 27, 2014 #8

    e.bar.goum

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    The physical explanation is just going to be Maxwell's equations written out as a sentence. The physical explanation you want is encoded in the mathematics.
     
  10. Oct 27, 2014 #9

    Drakkith

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    The EM wave spreads out as it travels, which reduces both the field strength and the energy of any section of the EM wave. Total energy of the wave remains the same, however.
     
  11. Oct 27, 2014 #10

    Orodruin

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    The physics explanation is the mathematical one, simply because physics is based on quantitative predictions using mathematical models. In some cases it might be possible to describe the mathematical framework in conceptual terms, but it is always going to be a likeness, not a precise statement.
     
  12. Oct 27, 2014 #11

    Simon Bridge

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    I was building Drakkith's answer, but the question is more about propagation so anticipating...
    ... mathematics is the language of physics - mathematical explanations are the physical ones. All the others are artistic answers.

    Imagine we can suddenly switch on a point charge. (Worry about how we may do that later.)
    We do this at t=0, relativity means that it takes some time for the electric field to reach farther out. It takes 1s to reach 1 light-second away and so on (electric fields travel at the speed of light.)
    This is a time-varying electric field, and the change in the field is what travels out.

    Any changing electric field is accompanied by a changing magnetic field and vice versa.
    (That's actually two of Maxwell's equations.)

    All this is pretty inadequate but it may help you get a glimmering.
     
    Last edited: Oct 27, 2014
  13. Oct 27, 2014 #12
    ... Which I cannot interpret because I lack knowledge of mathematics
    ... Which is why I come to a physics forum for help
     
  14. Oct 27, 2014 #13

    NTW

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    I propose a 'mental experiment', a sort of 'literary answer'.

    Let's imagine a point source in space, emitting light for 1/300000 s. The light will propagate as a spherical shell 1 km thick, and the energy contained in that shell will be the same, one second or one hour after the flash... The difference will be the energy density, but not the absolute value of that energy, that will remain constant.
     
  15. Oct 27, 2014 #14

    Simon Bridge

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    ... and we cannot help you unless you are prepared to acquire the knowledge ;)
    You'll just have to accept that EM waves travel through space is a fact of Nature which has been empirically confirmed.

    What do you need to know for?
     
  16. Oct 27, 2014 #15
    It wouldn't be perfectly spherical though would it? Because the point charge in oscillating in one plane?

    I do accept that this happens. I am asking why it happens.
    For my own understanding
     
  17. Oct 27, 2014 #16

    Orodruin

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    Without knowledge of mathematics, you will have to accept that certain things can only be described with analogues which are more or less flawed in nature. Some are going to be good enough to get an intuition about the particular phenomenon, but others will not. If you really want to understand on a more fundamental level, it is necessary to learn mathematics.

    Compare this to reading a poem by some great artist. If you do not speak the language, you will need a translation and more often than not translated poems simply are not the same as the original and several subtleties will be lost in translation.
     
  18. Oct 27, 2014 #17

    NTW

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    It doesn't matter, perfectly spherical or not, for the purpose of the mental experiment.
     
  19. Oct 27, 2014 #18
    Thanks, this is more what I was looking for. I know that the change in the field is what is traveling.

    But why is it that an unchanging electric field does not affect things an infinite distance away, but a changing electric field does?
    But it would not be perfectly spherical right? Because if the point charge is oscillating vertically, then directly above the point charge there would be no change in electric field?

    EDIT: There would be change in electric field, but the change would be oscillating in the direction of travel, like a sound wave right?
     
  20. Oct 27, 2014 #19

    Simon Bridge

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    ... this is false.
    Where are you getting these ideas from?

    Note: if you had an oscilating electric charge, and it was oscillating vertically, then that implies there is gravity. You don't want to include gravity, that's an un-needed complicaton. But we do need a label for the oscillation axis and "oscillation axis" is a bit much to write. Lets say the charge bobs up and down on the z-axis. We can pick the +z direction as the direction of the first displacement.

    Some distance along the +z axis, would be "directly above" in your description.
    An observer there would have an electric charge getting closer and then further away.
    The electric field strength varies with distance.
    This means the electric field strength is getting bigger and smaller with time.
     
    Last edited: Oct 27, 2014
  21. Oct 27, 2014 #20

    Nugatory

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    If you want a perfectly spherical wavefront, symmetrical in all directions, you'll have to generate it in a different wa... But this is a digression from the original question about how electromagnetic radiation propagates so should be discussed in a different thread.
     
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