How can I calculate the work needed to pull a toboggan up an inclined hill?

ka7
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[SOLVED] Work and energy

Hello, I've been having difficulty with this question...

Homework Statement



A 25.6kg child pulls a 4.81kg toboggan up a hill inclined at 25.7° to the horizontal. The vertical height of the hill is 27.3 m. Friction is negligible. Determine how much work the child must do on the toboggan to pull it at a constant velocity up the hill.



Homework Equations



W=FD COS (ANGLE)

The Attempt at a Solution



I tried using the equation above...and i tried adding the masses ...I got the wrong answer. The force, I used F=mg
w=mgd cos (angle)
=(4.81) (9.8) (27.3) cos (25.7)
=1.15 x 10^3 J
the answer 1.29 x 10^3 J but I'm not geting that...:confused:
 
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Welcome to the forums ka7,

HINT: What is the change in gravitational potential energy of the toboggan? (Much easier :wink:)
 
You should recheck what the D in your formula means. It is presumably NOT the vertical height of the hill.
 
Thanks, i figured out what i was doing wrong:smile:
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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