How Can I Calculate Time Dilation Between Two Observers?

Click For Summary

Discussion Overview

The discussion revolves around calculating time dilation between two observers, one on Earth and the other in a spacecraft traveling at a significant speed. The focus is on the application of the time dilation formula to determine how much time must pass for the two observers' watches to differ by one second, considering relativistic effects.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant expresses confusion about their calculations and notes a discrepancy between their result and the answer provided in a textbook.
  • Another participant requests clarification on the calculations attempted by the first participant to provide assistance.
  • A later post reiterates the original question and hints at the relationship between the proper time (T_0) and the dilated time (T_1) in the context of the problem.
  • One participant claims that approximately 5.449 seconds of Earth time will result in the spacecraft being one second behind, suggesting a specific outcome based on their calculations.
  • There is a suggestion that Earth time should be positioned on the left side of the equation used for calculations.

Areas of Agreement / Disagreement

Participants have not reached a consensus, as there are differing interpretations of the calculations and the application of the time dilation formula. The discussion remains unresolved regarding the correct approach and final answer.

Contextual Notes

Some assumptions about the initial conditions and the application of the time dilation formula may be missing or unclear. The discussion does not resolve the mathematical steps involved in the calculations.

crazynut52
Messages
11
Reaction score
0
I have the attached equation
but when I plug it, I don't get the same answer as in the back of the book...

Here is the question

Two observers, A on earth, B in a spacecraft whose speed is 2.0X10^8 m/s both set their watches to the same time, when the ship is abreast the earth.

How much time must elapse by A's reckoning before the watches differ by 1.00 seconds?
 

Attachments

  • equation.jpg
    equation.jpg
    1.8 KB · Views: 592
Physics news on Phys.org
What did you plug in? We can't help you if we don't know what you've tried to do.
 
crazynut52 said:
I have the attached equation
but when I plug it, I don't get the same answer as in the back of the book...
Here is the question
Two observers, A on earth, B in a spacecraft whose speed is 2.0X10^8 m/s both set their watches to the same time, when the ship is abreast the earth.
How much time must elapse by A's reckoning before the watches differ by 1.00 seconds?
Hint: which one is bigger, [itex]T_0[/itex] or [itex]T_1[/itex]?
 
After approx 5.449 secs of Earth time, the spaceship will be 1 sec. behind.
In your thumbnail, Earth time should be on the left of the equation.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 26 ·
Replies
26
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 88 ·
3
Replies
88
Views
8K
  • · Replies 42 ·
2
Replies
42
Views
5K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 65 ·
3
Replies
65
Views
13K