How can I derive the hydraulic equation using conservation of energy and work?

  • Context: High School 
  • Thread starter Thread starter bdolle
  • Start date Start date
  • Tags Tags
    Derivation Hydraulic
Click For Summary

Discussion Overview

The discussion revolves around deriving the hydraulic equation using principles of conservation of energy and work. Participants explore the relationship between forces and areas in a hydraulic system, specifically focusing on the formula deltaF = rho*g*(A1+A2)d2. The scope includes theoretical reasoning and mathematical derivation related to hydraulics.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses difficulty in deriving the hydraulic formula and requests a step-by-step explanation using conservation of energy.
  • Another participant suggests that the problem is strictly hydrostatics and not energetics, proposing to start from a specific equation related to force and area ratios.
  • A later reply provides a derivation that leads to the desired formula, using substitutions and simplifications based on the relationships between the variables involved.
  • Some participants request diagrams to clarify the forces involved in the equation.

Areas of Agreement / Disagreement

There is disagreement regarding the approach to the problem; some participants advocate for an energetics perspective while others assert that it should be treated as a hydrostatics problem. The discussion remains unresolved as to which approach is more appropriate.

Contextual Notes

Participants have not reached a consensus on the necessity of using conservation of energy versus hydrostatics for this problem. There are also unresolved assumptions regarding the definitions and relationships of the variables involved in the derivation.

bdolle
Messages
10
Reaction score
1
Hey All,

Question about hydraulics. Can't seem to find anyone videos or material to walk me through how to get the formula deltaF = rho*g*(A1+A2)d2

Any takers?

My book states: The conclusion is conservation of evergy. Work is done on the liquid by a small force pushing the liquid through a large displacement. Work is done by the liquid when it lifts the heavy weight through a small distance. a full anaylsis must consider the fact that the graviational potetial energy of the liquid is also changing, so we can't simply equate the output work to the input work. but you can see energy considerations require piston 1 to move farther than piston 2.

As a homework problem you can show that force 1 much increase by ... [insert formula above].

No I can't show it as a homework problem. Been trying for the last 2 hours. I have been searching the internet and can't find any explanations.

Please show me via work and conservation of energy how to derive this formula. Please spell out each step and go slow. Thank you!
 
Physics news on Phys.org
Can you please provide a diagram showing the force that this equation is supposed to be calculating?
 
Chestermiller said:
Can you please provide a diagram showing the force that this equation is supposed to be calculating?

Here you go. Let me know if you need more. Thanks.
 

Attachments

  • IMG_0362.JPG
    IMG_0362.JPG
    37.6 KB · Views: 667
  • IMG_0362.JPG
    IMG_0362.JPG
    37.6 KB · Views: 558
  • IMG_0363.JPG
    IMG_0363.JPG
    52.8 KB · Views: 531
  • IMG_0364.JPG
    IMG_0364.JPG
    46 KB · Views: 539
The solution to your homework problem does not involve energetics. This is strictly a hydrostatics problem. The starting point should be equation 5.11, or, in a slightly different form: $$F_1=F_2\frac{A_1}{A_2}+\rho g h A_1$$The question is "how much does the force F1 have to increase to achieve the new height difference d1+h+d2 (where d1 is the amount that the left level moves down)?"
 
Last edited:
Chestermiller said:
The solution to your homework problem does not involve energetics. This is strictly a hydrostatics problem. The starting point should be equation 5.11, or, in a slightly different form: $$F_1=F_2\frac{A_1}{A_2}+\rho g h A_1$$The question is "how much does the force F1 have to increase to achieve the new height difference d1+h+d2 (where d1 is the amount that the left level moves down)?"

So deltaF = F1 - F1 (where h is changed to (h+d1+d2)).

I get rho*g*A1*(d1+d2)=deltaF. we can sub "d2 = d1A1/A2" like they show in the book... But this will not help us. Instead use "d1=d2A2/A1" and sub this into d1 and we get rho*g*A1*(d2A2/A1+d2) which simplifies to rho*g*d2*(A2+A1) which is what we were looking for.

Got it.

THANKS
 
  • Like
Likes   Reactions: Chestermiller

Similar threads

  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K