How can I determine the parabola of a projectile?

  • Context: High School 
  • Thread starter Thread starter CallMeDirac
  • Start date Start date
  • Tags Tags
    Parabola Projectile
Click For Summary

Discussion Overview

The discussion revolves around determining the equation that describes the parabolic trajectory of a projectile. Participants explore the necessary components, including lateral and vertical velocities, and the effects of gravity on the motion. The conversation includes attempts to formulate equations and clarify concepts related to projectile motion.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant expresses confusion about how to formulate the equation for projectile motion, mentioning the need for lateral and vertical velocities.
  • Another participant suggests using the equations $$x = ut\cos \theta$$ and $$y = ut\sin \theta -\frac{1}{2}gt^2$$ as a starting point.
  • There is a discussion about the notation used in equations, with some participants pointing out formatting issues with LaTeX.
  • One participant attempts to define $$\Delta x^2$$ and $$\Delta y$$ in terms of slope but acknowledges the need to factor in gravity and deceleration.
  • Another participant requests clarification on the components of the suggested equations, indicating a lack of familiarity with the physics involved.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the formulation of the projectile motion equation, and multiple viewpoints and levels of understanding are present throughout the discussion.

Contextual Notes

Some participants express uncertainty about the correct application of equations and the role of gravity in the motion, indicating potential gaps in understanding or missing assumptions.

Who May Find This Useful

This discussion may be useful for individuals seeking to understand the basics of projectile motion, particularly those who are new to physics or looking for clarification on the relevant equations and concepts.

CallMeDirac
Messages
46
Reaction score
11
I have been puzzling over an equation that could be made to show the parabola of a projectile.
So far I have determined that the lateral and vertical velocities are needed, the lateral velocity should determine the x² function but after that I am stuck.

To specify I refused to look this up as that would be admitting defeat so I figured this was second best.
 
Physics news on Phys.org
CallMeDirac said:
Summary:: I need help on this

I have been puzzling over an equation that could be made to show the parabola of a projectile.
So far I have determined that the lateral and vertical velocities are needed, the lateral velocity should determine the x² function but after that I am stuck.

To specify I refused to look this up as that would be admitting defeat so I figured this was second best.
You need to post what you've done so far. Try to use Latex if you can:

https://www.physicsforums.com/help/latexhelp/

For example, I guess you have: $$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$

If you reply to this post you should see what I typed to get those formatted equations.
 
  • Like
Likes   Reactions: CallMeDirac
PeroK said:
You need to post what you've done so far. Try to use Latex if you can:

https://www.physicsforums.com/help/latexhelp/

For example, I guess you have: $$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$

If you reply to this post you should see what I typed to get those formatted equations.
\delta x^2 + \delta y + h

Is all I have but I need to account for gravity and find the rate of deceleration
 
CallMeDirac said:
\delta x^2 + \delta y + h

Is all I have but I need to account for gravity and find the rate of deceleration
That didnt work
 
CallMeDirac said:
That didnt work
You're short of a few dollars! You deleted the dollar signs that delimit the Latex.
 
PeroK said:
You're short of a few dollars! You deleted the dollar signs that delimit the Latex.
$$ \Delta x^2 + \Delta y + h $$
?
 
CallMeDirac said:
$$ \Delta x^2 + \Delta y + h $$
?
yes
 
CallMeDirac said:
$$ \Delta x^2 + \Delta y + h $$
?
That's not an expression I can make any sense of.
 
PeroK said:
You're short of a few dollars! You deleted the dollar signs that delimit the Latex.

So far I have

$$ \Delta x^2 + \Delta y + h $$

$$ \Delta x^2 $$ being the denominator in the slope and $$ \Delta y $$ being the numerator ( rise/ run for slope) and H being the height from which it is fired, but I need to factor in gravity and deceleration
 
  • #10
CallMeDirac said:
So far I have

$$ \Delta x^2 + \Delta y + h $$

$$ \Delta x^2 $$ being the denominator in the slope and $$ \Delta y $$ being the numerator ( rise/ run for slope) and H being the height from which it is fired, but I need to factor in gravity and deceleration
That makes no sense.

If you are trying to do what I think you are doing, you need to start with this:$$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$
 
  • #11
PeroK said:
If you are trying to do what I think you are doing, you need to start with this:$$x = ut\cos \theta, \ y = ut\sin \theta -\frac{1}{2}gt^2$$

Can you explain each part.
Sorry, I am a bit new to physics
 
  • #12
CallMeDirac said:
So far I have

$$ \Delta x^2 + \Delta y + h $$

$$ \Delta x^2 $$ being the denominator in the slope and $$ \Delta y $$ being the numerator ( rise/ run for slope) and H being the height from which it is fired, but I need to factor in gravity and deceleration
The real Paul Dirac would never have done anything like that! :wink:
 

Similar threads

  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 169 ·
6
Replies
169
Views
16K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 34 ·
2
Replies
34
Views
12K
  • · Replies 3 ·
Replies
3
Views
9K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 11 ·
Replies
11
Views
3K