How can I determine the voltage across a 6k ohm resistor using Ohm's Law?

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To determine the voltage across a 6k ohm resistor using Ohm's Law, one must first establish the current flowing through the resistor. The initial poster struggled with the problem despite applying Kirchhoff's laws and attempting to convert voltage sources to current sources. A helpful response suggested equating the voltage across the current generator to two expressions involving the current, allowing for the calculation of the current I1. Once I1 is known, the voltage across the resistor can be easily calculated. Clear documentation of the steps taken is crucial for identifying any errors in the approach.
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Can someone please help me with this problem?? I tried kcl, kvl, and nothing is working... the voltage across the 6k ohm resistor should be equal to 6 volts! but I am never able to get this answer.
please help

problem: Determine the voltage across the resister with 6 k(ohms)..
 

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come on someone help:S
 
Did you read the first post in this forum (the FAQ)? It says:

"1) Did you show your work? Homework helpers will not assist with any questions until you've shown your own effort on the problem. Remember, we help with homework, we don't do your homework. We already passed those classes, it's your turn to do so. "
 
man, I've been working all day long yesterday with the problem. I've already told you i used kvl and kcl on the nodes and nothing worked, i tried changing the voltage source into a current source and still it didnt work.. i tried finding equivalent resistors .. and still .. the same thing, I am never getting a right answer.. so can u please help?
 
Just don't say say what you did.
SHOW us the equations so we know where you went wrong.
 
nevermind.. thnks for the help ...
 
anyways if someone is willing to help just do please. and don't ask to add my work.. because I've already told u wat i did..
 
Prob.PNG


See the diagram above.

I tried this and got the right answer.

Voltage V is the voltage across the current generator. I1 is the current going left from there towards the 8 Volt supply.

I put the voltage V equal to two things containing I1. Just Ohms Law.
These are then equal to each other so you can work out I1.

Once you know that you can work out the voltages.
 

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