How can i find the Potential difference?

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Homework Statement


Through what potential difference must an electron be accelerate, starting from rest, to acquire a speed of 0.99c?

vf=0.99c(m/s), vi=0(m/s), m=9.11e-31(kg), q=1.6e-19(C)

Homework Equations



E=γmc^2=V*q

The Attempt at a Solution


I plugged in all knowns in the equation and find V(emf).

What i got is 3.63e6 eV but the answer is 3.1e6 V.

What did i do wrong in the progress??
 
on Phys.org
The voltage gives the electron extra energy over its rest energy, mc^2. So Vg=mc^2(γ-1).

ehild
 
But how does (γ-1) come from??
 
ehild, Never mind, i got it!

But should the unit be eV rather than V?
 
The question is potential difference, that is volts. But the change of energy of the electron is the same number in eV as the acceleration voltage: 1 elementary charge times U potential difference is 1*U =U eV.

ehild
 

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