I How Can I Integrate the Equation for a Rocket's Velocity?

  • I
  • Thread starter Thread starter DonDiablo
  • Start date Start date
  • Tags Tags
    Example Rocket
AI Thread Summary
The discussion centers on solving the problem of a rocket's acceleration under a constant force while losing mass at a constant rate. The user presents the equation for acceleration, a = F/(m0 - mL*t), and seeks assistance in integrating this to find the rocket's velocity. A solution is provided using u-substitution, leading to the velocity equation v = -(F/mL)ln(1 - (mL/m0)t) + v0. The user expresses gratitude for the guidance on the substitution method, highlighting its complexity. The conversation emphasizes the mathematical challenges associated with variable mass systems in physics.
DonDiablo
Hi - I just thought of a (relatively) simple example: Here is the problem I can't solve due to my disability to integrate the resulting equation:

I thought about a rocket that gets accelerated by a constant force F... Since the rocket is burning fuel and therefor losing mass at a conatnt rate its acceleration is not constant. Its mass is given by m=m0 - mL*t - with m0 being its mass at the start of the operation and mL being the rate at which it is losing weight (being constant). Since the force with which the rocket is accelerated is constant I get the following equation:

F= (m0-(m/T)*t)*a now i want to form that so I get "a" which I want then to integrate after t to get a formula for the rockets velocity! a=F/(m0-(m/T)*t)! This is the formula I don't know how to integrate! Help would be greatly appreciated! Lg Don
 
Physics news on Phys.org
DonDiablo said:
I want then to integrate after t to get a formula for the rockets velocity!
$$a=\frac{dv}{dt}=\frac{F}{m_{0}-m_{L}t}$$
$$dv=\frac{Fdt}{m_{0}-m_{L}t}$$
$$\int dv=\int\frac{Fdt}{m_{0}-m_{L}t}$$
Using a u-substitution ##u=1-m_{L}t/m_{0}##,
$$\int dv=-\frac{F}{m_{L}}\int\frac{du}{u}$$
$$v=-\frac{F}{m_{L}}\text{ln}(u)+C$$
$$v=-\frac{F}{m_{L}}\text{ln}\left(1-\frac{m_{L}}{m_{0}}t\right)+v_{0}$$
 
Last edited:
Thanks a lot! I know that this is just a standard example but it still amazes me hoe you found the substitution! Wouldn't have come there so easy! Lg Don
 
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...
Back
Top