How Can I Prove y'(t) = x(t) * h'(t) and y'(t) = x'(t) * h(t)?

benfrankballi
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how would I show that y'(t) = x(t) * h'(t) and y'(t) = x'(t) * h(t)

I know that in an LTI system y(t) = x(t) * h(t) = \int x(\tau) * h(t-\tau) from \infty to -\infty

But how would I go about trying to prove the first two equations?
 
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Why not just differentiate the convolution integral:

\frac{d}{dt}\int_{-\infty}^{\infty} x(\tau) h(t-\tau)d\tau=\int_{-\infty}^{\infty} x(\tau)h'(t-\tau)d\tau=x(t)*h'(t)
 
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