How can I simplify this expression using factoring?

AI Thread Summary
To simplify the expression 2a^2*b^2*c^2 + (a+c)^2*(a+b)^2*(b+c)^2 - a^2*c^2(a+c)^2 - (a+b)^2*a^2*b^2 - (b+c)^2*b^2*c^2 = 2abc(a+b+c)^3, it is recommended to expand and group the terms strategically. Using factoring techniques, such as recognizing patterns like (a-b)^2 = (a+b)(a-b), can aid in simplification. Breaking down the expression into manageable parts and working through them individually may reveal a clearer path to the solution. Drawing lines to separate terms can help visualize the problem better. Persistence and multiple attempts are key to tackling complex expressions.
jesuslovesu
Messages
185
Reaction score
0

Homework Statement


Show
2a^2*b^2*c^2 + (a+c)^2*(a+b)^2*(b+c)^2 - a^2*c^2(a+c)^2 - (a+b)^2 * a^2 * b^2 - (b+c)^2*b^2*c^2 = 2abc(a+b+c)^3


Homework Equations





The Attempt at a Solution



Well I actually tried to expand all of the exponential terms but that ended up being a total mess and wasn't even remotely obvious... My professor said using something like (a-b)^2 = (a+b)(a-b) would help, but I don't quite see how that would help.. can anyone give me a hint?
 
Physics news on Phys.org
ya only tried once? I find that I need to work through complicated expressions multiple times. Don't give up keep after it. You may want to show us some of your work. If you do pleas go to the tutorials forum and read the latex thread.
 
Try it in parts. When I solve problems that look like a mess I'll draw lines down a paper and group it by addition/subtractions. That way you're just dealing with each part individually.

<br /> \underbrace{2a^2*b^2*c^2}_{First} + \underbrace{(a+c)^2*(a+b)^2*(b+c)^2}_{Second} - \underbrace{a^2*c^2(a+c)^2}_{Third} - \underbrace{(a+b)^2 * a^2 * b^2}_{Fourth} - \underbrace{(b+c)^2*b^2*c^2}_{Fifth} &amp;=&amp; \underbrace{2abc(a+b+c)^3}_{Sixth}<br />

Now that you've grouped off your terms. Expand these out, simplify. The solution may become obvious (or at least easier) to find. When you're done, you may be left with something as simple as a quadratic, but don't quote me on that. I've not done the problem myself.
 
Last edited:
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top