MATLAB How can i solve these equations in Matlab?

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The discussion revolves around solving a system of equations with multiple unknowns, specifically focusing on five equations and ten unknowns. The user initially seeks help to solve for specific variables (p, η0, ηr, θ0, θr) but faces challenges due to the underdetermined nature of the system. After providing values for the variables, the conversation shifts to a step-by-step approach for solving the equations. It is suggested to manipulate equations 4 and 5 to derive a simpler equation that leads to determining the value of Z, which is found to be zero. Consequently, this results in α also being zero. The discussion highlights the importance of ensuring the correctness of the equations and values used in the calculations.
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Equation 1:
upload_2015-5-17_22-8-7.png

Equation 2:
upload_2015-5-17_22-8-24.png

Equation 3:
upload_2015-5-17_22-8-36.png

Equation 4:
upload_2015-5-17_22-8-47.png

Equation 5:
upload_2015-5-17_22-8-59.png


I would like to solve
upload_2015-5-17_22-9-25.png
, (not the one with a star)
and i want to define values for p, η0, ηr, θ0, θr.
i have tried to solve them, but didn't work,
can someone please help and show me step by step?
 
Last edited:
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What exactly are you trying to do? I count 10 unknowns (α, α*, p, η0, ηR, θ, θ0, S0, Z, β), and only 5 equations. So the system is underdetermined and there are an infinite number of possible solutions. You either need to fix some of the values or find more equations until the number of equations equals the number of unknowns. What exactly have you tried so far?
 
phyzguy said:
What exactly are you trying to do? I count 10 unknowns (α, α*, p, η0, ηR, θ, θ0, S0, Z, β), and only 5 equations. So the system is underdetermined and there are an infinite number of possible solutions. You either need to fix some of the values or find more equations until the number of equations equals the number of unknowns. What exactly have you tried so far?
Actually, i have values for p, η0, ηr, θ0, θr,
for example:
p=101325,
η0=4.43,
ηr=0.181,
θ0=313.15,
θr=373.15,
also, as you can see, it is possible to solve α , because these 5 equations can be combined into 1
 
OK, that makes more sense. So can you do the following?

(1) Solve equation 4 for the ratio β/S0.
(2) Divide equation 5 by S0 to get β/S0 on the LHS. Then plug the result from step 1 into this and solve this equation for Z.
(3) Take the result from step 2 and plug it into equation 3, then solve this equation for α.

Edit:

Actually, I see now that it is even simpler than that. You can combine equations 4 and 5 to give:

(1+5.1E-9*p)^Z = 1

Solve this for Z and plug it into equation 3 to give α.
 
Last edited:
Looking more at your equations. Equations 4 and 5 together imply that:

(1+5.1E-9*p)^Z = 1

Since p = 101325, (1+5.1E-9*p) = 1.0005, so this equation is only satisfied for Z = 0. Equation 3 then implies that α=0. Are you sure this is all correct, or am I missing something?
 

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