How can I use 4, 4, and 4 to result in the number 31?

[turkldo]

How can I use 4, 4, and 4 to result in the number 31? You can perform any operation the 4's, but you can only use three 4's.

 

[jcsd]

bah! I can do it with only 2 4's:

[cosh(4) + 4] = 31

 

[A_I_]

what do u mean by cosh.. i didn't understand the h?

 

[turkldo]

You are required to use all three of the 4's. I should have been more specific...sorry.

 

[turkldo]

AI,

JCSD used the Hyperbolic Cosine function.

The cosh function operates element-wise on arrays. The function's domains and ranges include complex values. All angles are in radians.

Y = cosh(X) returns the hyperbolic cosine for each element of X.

Now, cosh 4 = 27.308

 

[A_I_]

how can we do it on a calculator.. i mean the cosh.. or does it have any formula?

 

[Tide]

\cosh x = \frac {e^x + e^{-x}}{2}

 

[turkldo]

I have a TI-85. On it you select 2nd, Math. Next you press F4 for the HYP menu. Then you choose the type of hyperbolic function you want to use.

 

[Chrono]

I have a TI-85. On it you select 2nd, Math. Next you press F4 for the HYP menu. Then you choose the type of hyperbolic function you want to use.

Or you could just type in (e^x + e^-x)/2

 

[JasonRox]

4^0 + 4^0 ... + 4^0 = 31

Technically I didn't use any four's since it is exponent 0.

It is possible I know that.

You have many options to work with.

 

[recon]

Is this a brain teaser or a question you found in a mathematics textbook?

 

[Tide]

4^{4-\sqrt 4} = 31

... base 5! :-)

 

[gazzo]

Oooh. Does this count?

<br /> {\lfloor}\int_{4}^{4+4} cosh (\theta + \theta + \theta){\rfloor}<br />

 

[gazzo]

oh, ignore my last post. bah. bad calculator! bad bad!