How can the drift velocity and voltage be determined for two different samples?

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SUMMARY

This discussion focuses on determining the Hall voltage and drift velocity for two samples: pure sodium (Na) and indium antimonide (InSb). The current of 100mA is applied across samples measuring 5x1x5mm in a magnetic field of 0.1T. The calculations involve using the formula for drift velocity, v_d = I/(A*N_e*(-e)), where I is the current, A is the cross-sectional area, and N_e is the electron density. The effective masses provided (m_e* = 0.015m_0 and m_h* = 0.18m_0) are relevant for understanding the material properties but not directly needed for the calculations of part b.

PREREQUISITES
  • Understanding of Hall effect principles
  • Familiarity with drift velocity calculations
  • Knowledge of effective mass in semiconductor physics
  • Basic proficiency in electromagnetism
NEXT STEPS
  • Calculate Hall voltage using the formula V_H = B * I * L / (n * e) for both Na and InSb
  • Research electron density (N_e) values for pure sodium and indium antimonide
  • Explore the relationship between effective mass and mobility in semiconductors
  • Learn about the applications of Hall effect measurements in material science
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Students in physics or materials science, researchers studying semiconductor properties, and anyone preparing for assignments involving the Hall effect and drift velocity calculations.

Larsson
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Not sure if this should be in this forum, but let's try.

The problem is about 2 samples. One pure Na and one InSb.
I want to determine the hall voltage when we send a current of 100mA trough the samples and the magnetic field is B = 0.1T. The samples are dimensioned "squared" 5x1x5mm. We send our current into the 5x1 side and out at the opposit side.

I start with stating F = 0 = q(E +v x B)
Here I have everything except for the E that I want to find, and v, the driftvelocity of the electrons. How am I supposed to find my v with the information given? Would appreciate if you could show the calulations eventough it's not populair here, having my test soon.

this is part b of an assignment. In the a part they give m_e* = 0.015m_0 and m_h* = 0.18m_0. Where * means the efficient mass. Dont really think that's needed in the b part, but just to be sure.
 
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Never mind
J = N_e *(-e) * v_d
J = I/A
I/A = N_e *(-e) * v_d
v_d = I/(A*N_e*(-e))
 

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