How can the drift velocity and voltage be determined for two different samples?

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To determine the Hall voltage for pure Na and InSb samples, a current of 100mA is applied through each sample in a magnetic field of 0.1T. The samples are 5x1x5mm in size, with current entering through the 5x1 side. The drift velocity (v_d) can be calculated using the equation v_d = I/(A*N_e*(-e)), where J = N_e *(-e) * v_d and J = I/A. The effective masses of electrons and holes provided in part a of the assignment may not be necessary for this calculation. Understanding these relationships is crucial for solving the assignment effectively.
Larsson
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Not sure if this should be in this forum, but let's try.

The problem is about 2 samples. One pure Na and one InSb.
I want to determine the hall voltage when we send a current of 100mA trough the samples and the magnetic field is B = 0.1T. The samples are dimensioned "squared" 5x1x5mm. We send our current into the 5x1 side and out at the opposit side.

I start with stating F = 0 = q(E +v x B)
Here I have everything except for the E that I want to find, and v, the driftvelocity of the electrons. How am I supposed to find my v with the information given? Would appreciate if you could show the calulations eventough it's not populair here, having my test soon.

this is part b of an assignment. In the a part they give m_e* = 0.015m_0 and m_h* = 0.18m_0. Where * means the efficient mass. Dont really think that's needed in the b part, but just to be sure.
 
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Never mind
J = N_e *(-e) * v_d
J = I/A
I/A = N_e *(-e) * v_d
v_d = I/(A*N_e*(-e))
 
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