How can the integral of a complex function be simplified?

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Homework Statement



[itex]\int sin e^{-x}+e^x cos e^{-x}\,dx[/itex]

Find the integral above

Homework Equations





The Attempt at a Solution



I tried substituting [itex]u=e^{-x}[/itex], but i get [itex]\int \frac{sin u}{u}+\frac{cos u}{u^2} \,du[/itex], which is non-integrable function.
 
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Thanks. I didn't notice that
 
ehild said:
What is the derivative of ##e^x\cos(e^{-x})##?

ehild

A second way is to try to transform the cos into a sin function. That leads to the hope that an integration by part will work by starting with

[itex]e^x cos (e^{-x}) = \frac{d e^x}{dx} \cos (e^{-x})[/itex]

and sure enough that works.