How Can Trigonometric Substitution Simplify the Integral of x²/√(1-x²)?

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SUMMARY

The forum discussion focuses on simplifying the integral of the function \(\int^{0}_{1}\frac{x^{2}}{\sqrt{1-x^{2}}}dx\) using trigonometric substitution. The substitution \(x = \sin(\theta)\) is proposed, leading to \(dx = \cos(\theta)d\theta\). Participants emphasize the importance of replacing both \(dx\) and the square root in the denominator, and suggest using the identity \(\sin^2(\theta) = \frac{1 - \cos(2\theta)}{2}\) to facilitate the integration process. The discussion concludes with a recommendation to break the integral into simpler components for easier evaluation.

PREREQUISITES
  • Understanding of trigonometric identities, specifically \(\sin^2(\theta)\) and \(\cos(2\theta)\)
  • Familiarity with integral calculus and techniques for integration
  • Knowledge of substitution methods in integration
  • Basic understanding of the properties of definite integrals
NEXT STEPS
  • Study the method of trigonometric substitution in integral calculus
  • Learn how to apply the identity \(\sin^2(\theta) = \frac{1 - \cos(2\theta)}{2}\) in integration
  • Explore additional examples of integrals involving square roots and trigonometric functions
  • Review the process of changing variables in definite integrals
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for examples of trigonometric substitution in action.

kathrynag
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Homework Statement



\int^{0}_{1}\frac{x^{2}}{\sqrt{1-x^{2}}}

Homework Equations





The Attempt at a Solution


Let x=sintheta
dx=cos theta
\int^{0}_{1}\sin^{2}
Now I get stuck
 
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well, i believe

sin^2x=\frac{1-cos2x}{2} would help.
 
You don't show dx in your original integral, but it should be there. You need to replace it and the square root in the denominator, using your substitution.

In your substitution, dx = cos(theta) d(theta).
 
There's a trig formula that let's you express sin(theta)^2 in terms of cos(2*theta). Can you find it?
 
sutupidmath said:
well, i believe

sin^2x=\frac{1-cos2x}{2} would help.

so then i would make u=2x and du=2dx
 
kathrynag said:
so then i would make u=2x and du=2dx

well first you would break it into 1/2-1/2 cos(2x) then if you want you can make that substituion, that would work.
 
sutupidmath said:
well first you would break it into 1/2-1/2 cos(2x) then if you want you can make that substituion, that would work.

Ok, well that's what I meant.
 
:wink:
kathrynag said:
Ok, well that's what I meant.
 

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