How can water pressure be measured in m

AI Thread Summary
Water pressure can be measured in meters by using the concept of pressure head, which indicates the height of a column of water that corresponds to a specific pressure. In South Africa, a minimum residual pressure design criterion is set at 24 meters for water distribution systems, reflecting the pressure needed to push water to that height. The diameter of the pipe does not affect the pressure head, as pressure is determined solely by the height of the water column. Conversions between pressure units like pascals and pounds per square inch can be made, but pressure head is primarily used to express differences in pressure rather than standalone values. Understanding these principles is essential for developing educational materials for waterworks staff.
dacgray
Messages
5
Reaction score
0
How can water pressure be measured in "m"

Hi

I need to understand how minimum residual pressure can be measured in meters. At least I think its meters. The specific sentence in the abstract is:

"The South African civil engineering fraternity has grown to accept 24 m as the design criterion for minimum residual pressure in water distribution systems. However, the theoretical peak demand in many systems has increased beyond the point where minimum residual pressure exceeds 24 m – at least according to hydraulic models."

A copy of this paper can be found at
http://www.scielo.org.za/scielo.php?pid=S1816-79502009000200007&script=sci_arttext

I am developing material to help the South African waterworks department teach its staff along the lines of South African unit standard 254073, and while I am a skilled materials developer, I do not have a background in fluid dynamics. (It's South Africa)

Any help would be much appreciated.
 
Physics news on Phys.org


You can express pressure in 'head'.
http://en.wikipedia.org/wiki/Pressure_head

Ie the desgin pressure is that made by a column of water 24m high. Or the difference between atmospheric (for example) and another perssure is 24m.
 


Thanks for the reply,

So would a way that I could explain it be that if the 'head' in a water pipe is 24m, that pressure would be enough to push that water 24m up at normal g? Could I say that a head of 10 m is low pressure, and a head of 50m is high pressure.

another way that I could say it would be that a 24m high column of water would push down with 24m head of pressure. What effect would the diameter of the pipe have on this pressure?

Is there a way that I can convert between head, pascal and pounds per square inch?

Much appreciated.
 


While Pa is the SI unit for pressure there are various different units still in common usage. Below are a few of the most common ones and their corresponding relation to the standard atmosphere.

1 atm (Atmosphere) = 1.013E5 Pa = 1.013 Bar = 14.7 psi = 10.3m water = 760 mm Hg

* some of the above are approximate.
 


dacgray said:
Thanks for the reply,

So would a way that I could explain it be that if the 'head' in a water pipe is 24m, that pressure would be enough to push that water 24m up at normal g? Could I say that a head of 10 m is low pressure, and a head of 50m is high pressure.

another way that I could say it would be that a 24m high column of water would push down with 24m head of pressure. What effect would the diameter of the pipe have on this pressure?

Is there a way that I can convert between head, pascal and pounds per square inch?

Much appreciated.

You don't use pressure head to describe a stand alone pressure (its more convenient to simply use a pressure), it's used to describe a difference in pressure. This usualyl comes from experimental values.

As such diameter of the pipe would have no effect on the head. It simply says the difference between the two pressures is enough to send water up a colum 24m.

Just like is a swimming pool, if you have a 25m long pool the pressure at a given depth is the same as if you were in a 50m olympic pool.
 
Last edited:


Imagine a column of water of a given height h and of area A. What is the pressure P felt under that column?

So:

P = W / A where W is the weight of the column of water.

And:

W = m g where m is the mass of water and g is the acceleration of gravity.

m = rho V where rho is the density of water and V the volume of water.

V = A h

Putting everything together:

P = (m g) / A = (rho V g) / A

P = rho g h

Since rho and g can be assume constant for some specific cases, the pressure varies only with the height of the column of water, no matter what is the area of the column (hence the diameter of the pipe). This is how we can measure pressure in meter. This case was for water, but if you use the density of mercury (Hg) instead, you could measure in "mm Hg", i.e. "equivalent pressure felt under a column of mercury with a height of X millimeters".

The same logic applies to air pressure. If we feel a 101 kpa of air pressure on the ground, it is because of the weight of the air over our head that is pushing down on us due to gravity. (Although, in this particular case, rho and g will vary with height)
 


Thank you for your help
 
Back
Top