How can we prove the curvature of a space curve using regular parameterization?

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SUMMARY

The curvature of a space curve \( C \subset \mathbb{R}^{3} \) can be proven using the formula \( \kappa=\frac{\left\|\underline{\dot{r}}\times\underline{\ddot{r}}\right\|}{\left\|\underline{\dot{r}}\right\|^{3}} \) where \( \underline{r} \) is a regular parameterization. The discussion highlights the differentiation of the tangent vector \( t(u) \) and its relationship to curvature \( \kappa \) and the normal vector \( \underline{n} \). A recommended resource for further understanding is an introductory book on differential geometry.

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Homework Statement



Let \underline{r} be a regular parameterisation of a space curve C \subset R^{3}. Prove that

\kappa=\frac{\left\|\underline{\dot{r}}\times\underline{\ddot{r}}\right\|}{\left\|\underline{\dot{r}}\right\|^{3}} .

The Attempt at a Solution



We have

t(u)=\frac{\frac{dr}{du}}{\left\|\frac{dr}{du}\right\|}

so differentiating both sides wrt u we obtain

\frac{dt}{du}=\frac{\frac{d^{2}r}{du^{2}}}{\left\|\frac{dr}{du}\right\|}+\frac{dr}{du}\frac{d}{du}(\frac{1}{\left\|\frac{dr}{du}\right\|}).

Since

\frac{dt}{du}=\kappa\underline{n}

this gets me the curavture in terms of the desired bits (with n too) but I can't seem to get it to the desired result :\

Thanks for your help!
 
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