How can you calculate nonequilibrium torque and its effects on an extended body?

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SUMMARY

This discussion focuses on calculating nonequilibrium torque for extended bodies, particularly in the context of aircraft dynamics. It establishes that in equilibrium, forces and torques are balanced, resulting in zero net torque and constant velocity. However, in nonequilibrium scenarios, non-zero net torque leads to angular acceleration. The conversation emphasizes the importance of understanding the forces acting on the center of mass (CM) and how to adjust calculations when drag forces are not aligned with the CM.

PREREQUISITES
  • Understanding of basic physics concepts such as forces, torque, and angular acceleration.
  • Familiarity with equilibrium conditions in mechanics.
  • Knowledge of aircraft dynamics and the forces acting on an aircraft.
  • Ability to perform calculations involving forces and torques.
NEXT STEPS
  • Study the principles of nonequilibrium dynamics in extended bodies.
  • Learn how to calculate torque in non-equilibrium situations using specific examples.
  • Explore the relationship between drag forces and center of mass in aircraft motion.
  • Review resources on angular acceleration and its implications in real-world applications.
USEFUL FOR

This discussion is beneficial for physics students, aerospace engineers, and anyone involved in the study of dynamics and torque in mechanical systems.

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Can somebody give an example of nonequilibrium torque and how to go about doing calculations for it? So, for example, for an EQUILIBRIUM problem if you have an aircraft moving with constant velocity there's a drag force in one horizontal direction and a tension opposing it 2 m below the center of mass due to engine thrusters. There's also gravity at the CM and an opposing lift force. If it was nonequilibrium I'm guessing it would be not at constant velocity (would there be any other situation in which it would not be at equilibrum?). If you wish to determine the distance above the CM that the drag force acts, how would the calculations change?


At equilibrium, you set F_y and F_x to 0, and torque to 0 and work from there...
 
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