How can you determine the net force of a bottle

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SUMMARY

The net force of a bottle under 2 atm of pressure can be determined using the formula P=F/A, where P is the pressure, F is the force, and A is the area of the openings. For a bottle with a 1 cm diameter opening, the area is calculated as π/4 cm². When considering two openings, the total area is the sum of the individual areas, A1 + A2. The outside pressure does influence the net force, as it affects the pressure difference driving the fluid out of the bottle.

PREREQUISITES
  • Understanding of Bernoulli's equation
  • Familiarity with pressure concepts (P=F/A)
  • Knowledge of fluid dynamics and flow rate calculations
  • Basic geometry for area calculations
NEXT STEPS
  • Study Bernoulli's equation in detail
  • Learn about pressure differentials in fluid dynamics
  • Explore flow rate calculations for different opening geometries
  • Investigate the effects of external pressure on fluid flow
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Physics students, engineers, and anyone interested in fluid dynamics and pressure systems will benefit from this discussion.

Gmaximus
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How can you determine the net force of a bottle who's contents are kept under 2 atm of pressure, and it has a 1 cm opening for example?

a1v1=a2v2 doesn't seem to apply, and the flowrate=dav doesn't seem to either. I suspect it is bernoulli's equation, but I am unsure.

I know P=F/A, but how do you find the pressure? is it simply the pressure difference?
 
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Also, if the bottle has two openings facing in the same direction, how does that work? Do you add the area of the two holes and use that for area, or is it two separate cases?
 
Pressure is defined as "force divided by area" or P= F/A so F= P*A. You are given that the pressure is 2 atmospheres and the fluid is coming out an area of pi cm2 (I am assuming that the "1 cm" hole has radius 1 cm. If it is diameter= 1 cm, then the area is pi/4 cm2).

Yes, if you have two holes of area A1 and A2, then that is the same as 1 hole of area A1+ A2.
 
Does the outside pressure matter?
 

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