How Can You Factor the Trigonometric Expression sin^3(x)-cos^3(x)?

AI Thread Summary
To factor the expression sin^3(x) - cos^3(x), one can use the identity sin^2(x) + cos^2(x) = 1. The expression can be rewritten as (sin(x) - cos(x))(sin^2(x) + sin(x)cos(x) + cos^2(x)). The denominator sin(x) - cos(x) cancels out, leading to the simplified form of sin^2(x) + sin(x)cos(x) + cos^2(x). There is some confusion about whether the result should include a term with sin(x)cos(x). The discussion emphasizes the importance of factoring and using trigonometric identities effectively.
xCycLoNeX
Messages
2
Reaction score
0

Homework Statement



sin^3(x)-cos^3(x)
sin(x) - cos(x)

equals

1 + sin(x) + cos(x)

Homework Equations


Not sure :/


The Attempt at a Solution


Not sure where to even start.
 
Physics news on Phys.org
Are you sure that it's 1+sin(x)+cos(x) and not 1+sin(x)cos(x)?

Use the identity sin^2(x)+cos^2(x)=1.
 
Oh yeah, that was it.
 
sin^3(x)-cos^3(x)
-----------------
sin(x) - cos(x)

Try factoring the numerator, it may help you.
 
Back
Top