To factor the expression sin^3(x) - cos^3(x), one can use the identity sin^2(x) + cos^2(x) = 1. The expression can be rewritten as (sin(x) - cos(x))(sin^2(x) + sin(x)cos(x) + cos^2(x)). The denominator sin(x) - cos(x) cancels out, leading to the simplified form of sin^2(x) + sin(x)cos(x) + cos^2(x). There is some confusion about whether the result should include a term with sin(x)cos(x). The discussion emphasizes the importance of factoring and using trigonometric identities effectively.
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense.
Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities?
Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots.
Let ##f(x)=27x^{18}+bx^9+70##, then:
$$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$
$$b=27 \frac{q}{p}+70 \frac{p}{q}$$
$$b=\frac{27q^2+70p^2}{pq}$$
From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##.
How to find the greatest value of ##b##?
Thanks