How Can You Find ψ(x,t) from ψ(x) for a Free Particle?

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SUMMARY

The discussion focuses on deriving the time-dependent wavefunction ψ(x,t) for a free particle given the spatial wavefunction ψ(x) = (π/a)^(-1/4) * exp(-ax^2/2). Participants emphasize the importance of calculating the coefficient expansion function θ(k) using the integral θ(k) = ∫dx * ψ(x) * exp(-ikx) over the entire real line. While some suggest using the error function for evaluation, others recommend employing Gaussian integral techniques and complex analysis to simplify the process, highlighting the necessity of mastering these methods for future applications.

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Homework Statement


Consider the free-particle wavefunction,
ψ(x)=(pi/a)^(-1/4)*exp(-ax^2/2)

Find ψ(x,t)


The Attempt at a Solution



The wavefunction is already normalized, so the next thing to find is coefficient expansion function (θ(k)), where:

θ(k)=∫dx*ψ(x)*exp(-ikx) from -infinity to infinity

But this equation seems to be impossible to solve without error function (as maple 16 tells me).

Is there any trick to solve this?
 
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The error function has very nice properties at the infinity, so you should be able to compute the integral. Alternatively, you could use the apparatus of complex analysis to evaluate the integral.
 
Why not use some of the simple Gaussian integral tricks (like completing the square in the exponential)? Or am I missing something?
 
You can avoid the error function because of the limits on the integral, or equivalently, use the nice properties of the error function at those limits.

You should really learn to crank this integral out by hand, though. The techniques used are useful to know.
 

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