How charge acceleration is dependent on radiation of electromagnetic wave?

AI Thread Summary
Charge acceleration is linked to the emission of electromagnetic radiation, with larger charges radiating more photons. When an electron accelerates, it can lose energy through radiation, leading to deceleration, particularly in processes like synchrotron radiation. A free electron cannot emit a real photon without violating conservation laws, but it can interact with other particles, allowing for energy exchange. The relationship between energy loss and acceleration is quantified by a specific formula, indicating that acceleration results in radiation and energy loss. Overall, acceleration and radiation are inherently connected in electromagnetic interactions.
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Is there any mathematical relation between the value of charge(ie proton/electron) and radiation which is being emitted? I m sure energy is conserved in this process so does that mean electron decelerates in process of radiation ?
 
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Radiation which is emitted where?
If you have a particle with a larger charge (but otherwise identical), you can expect that it radiates more photons than another particle.

Energy conservation is a completely different area.

Deceleration is the same as acceleration (in terms of "increases absolute velocity"), just for different observers.

A free electron cannot emit a real photon without violating energy or momentum conservation. However, it can exchange virtual photons or emit real photons if more particles are involved in the process.
 
Well I've read that a accelerated charge releases EM wave..By doing so,charge loses its energy right? Which inturn results in decrease of velocity(deceleration as I meant)..So what's the relation which holds with energy released in this process and amount of acceleration..Hope u get my claim..THanking you
 
I think you mean synchrotron radiation. Yes, accelerated electrons can radiate away energy and therefore become slower (more important: less energetic).
 
mfb said:
A free electron cannot emit a real photon without violating energy or momentum conservation.

Does this mean violation of conservation of energy..??!
 
No, it means that a free electron does not emit a real photon.
Note that an electron in an electromagnetic field is not free, but can interact with other photons. The process "electron+photon -> electron+photon with different momenta" is possible.
 
The electron can be accelerated (decelerated) either transversely (synchrotron radiation) or longitudinally. Whenever there is acceleration, there is radiation. The rate of energy loss is
\frac{dW}{dt}=-\frac{e^{2} \dot{v}^2}{6\pi\epsilon_o c^3} where \dot{v} is the acceleration.
 
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