How come there are no neutron atoms?

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Straight forward question. What would prevent the process of a giant lump of neutrons from forming a stable nucleus?
 
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The strong nuclear force
Because neutrons have the same spin they cannot occupy the same energy level, so a nucleus of just neutrons can't get into the lowest energy state and so isn't stable,

Neutron stars could be thought of as a single nucleus of just neutrons - but they need gravity (and a lot of it) to hold them together
 
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There has been some talk about an element 0 - a nucleus with only neutrons. Wiki has some things to say on this neutronium element.
 
Stand alone neutrons decay into proton + electron + neutrino.
 
O.K,what sort of "atom" should we get from an uncharged nucleus?.What sort of chemistry would you expect?.Study the issue.Read Pais,"Inward Bound" and study the references at the chapter ends.Imagine a world with electromagnetism "switched-off",and then compare the proton/neutron.Are they different in such a world?,...,why is the quark-model such a good classification scheme?.Read Riordan "The Hunting Of The Quark".Study,...
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

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