How Deep Would the Water Ice Layer Be on the Moon?

AI Thread Summary
The discussion focuses on calculating the depth of a water ice layer on the Moon resulting from the combustion of Aerozine-50 used during Apollo missions. The user seeks clarification on whether to model the ice layer as a cylinder or a sphere, ultimately deciding on a cylindrical shape due to the Moon's flat surface at that scale. The problem involves using the density of water ice and the total mass of Aerozine-50 to determine the equivalent depth. There is also a correction noted regarding the chemical formula for dimethylhydrazine. The conversation emphasizes the importance of proper assumptions in solving the problem accurately.
GOsuchessplayer
Messages
9
Reaction score
0

Homework Statement



During the Apollo missions, each lunar module decelerated toward the surface of the moon by the oxidation of "Aerozine-50" fuel. Aerozine-50 is a blend of hydrazine, N2H4, and dimethylhydrazine, CH3()2N2H2, 50% by mass in each component (known to infinite precision). Nitrogen tetroxide, N2O4, was used as the oxidizing agent.

c. Determine the depth in centimeters of the equivalent water ice layer (density = 0.92 g/cm3) deposited on the surface if spread evenly over a circle 1.8 km in diameter.

Homework Equations



Assume that 2701 kg of Aerozine-50 was used in each deceleration, and that each component underwent ideal combustion according to the following unbalanced reactions:
N2H4+N2O4→N2+H2O (1)
CH3()2N2H2+N2O4→N2+H2O+CO2 (2)

The Attempt at a Solution



All I'm asking is if the ice layer is going to be cylinder or a sphere? I know how to do the problem I'm just not sure which they'd like.
 
Physics news on Phys.org
You have wrong parentheses in dimethylhydrazine, it should be (CH3)2N2H2.

Assume cylinder - at this scale surface of the Moon can be considered flat.
 
Last edited by a moderator:
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
View full post »

Hot Threads

Recent Insights

Back
Top