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How did this transition occur?

  • Thread starter kLPantera
  • Start date
  • #1
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lim as x-> 0 (2-cos3x-cos4x)/(x).

I'm not sure how the numerator became (1-cos3x)(1-cos4x)/(x)

What am I missing? Could someone please point it out? Is it a trignometric factoring formula I'm not thinking of?
 

Answers and Replies

  • #2
SammyS
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lim as x-> 0 (2-cos3x-cos4x)/(x).

I'm not sure how the numerator became (1-cos3x)(1-cos4x)/(x)

What am I missing? Could someone please point it out? Is it a trignometric factoring formula I'm not thinking of?
It's difficult to answer this without you providing more context, but here's a try.

(2-cos(3x)-cos(4x)) ≠ (1-cos(3x))(1-cos(4x)).

However, (2-cos(3x)-cos(4x)) = (1-cos(3x)) + (1-cos(4x)) .
 
  • #3
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So how did the numerator become: (2-cos(3x)-cos(4x)) = (1-cos(3x)) + (1-cos(4x))?
 

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